angularjs - 错误状态代码未被捕获

Question

我正在 try catch angular 资源的 HTTP 错误状态代码 (!=200)。
我的服务，我在其中定义了资源:
(apiService.js)

.factory('ApiService', function($resource, $http, localStorageService, CONFIG) {

    var base_api_url = api_url = CONFIG.api_url, api_version_prefix = CONFIG.api_version_prefix;

    return {
        userDevices: $resource(api_url+'/requestRegistration/userDevices/:action', {}, {
            registerDevice: {
                method: 'POST',
                params: {
                   action: ''
                }
            },
            verify: {
                method: 'POST',
                params: {
                   action: 'verify'
                }
            },               
        }
    }
});

我的 Controller 代码:

.controller('LoginCtrl', function(CONFIG, $scope, $state, $ionicPlatform, $ionicPopup, ApiService) {


    $scope.data = {
        username: null
    };

    $scope.registerDevice = function() {
        if($scope.data.username) { 
            var authenticationResponse = ApiService.userDevices.registerDevice({
                username: $scope.data.username
            });

            authenticationResponse.$promise.then(function(result) {
                // this is always fired, even then response code is 400 or 503 :( I am not able to check response status code.
                console.log(result);
                console.log('success!');
            }, function(error){
                // this code is not being exectued even when response status code is different then 200
                // its never executed at all :(
                console.log('error!');
            });
        }
    };


});

当我发送请求并收到响应代码 400/503 时，我认为应该执行函数(错误)代码，但事实并非如此。

相反，我在 $promise.then(function(result)(...) 中的代码已执行，但我无法检测到响应 HTTP 状态代码。

所以，我的问题:

为什么我的错误处理函数没有被执行？

如何检测 HTTP 响应状态代码？

Answer 1

第一.catch是 转换 拒绝履行。为防止转换，.catch方法需要throw错误。

   authenticationResponse.$promise.catch(function(error){
        alert('catched error!!!');
        //throw to chain error
        throw error;
    }).then(function(result) {
        // this is always fired, even then response code is 400 or 503 :(
        console.log(result);
        console.log('success!');
        //return to chain data
        return result
    }, function(error){
        // This should be executed when status code is different then 200?
        // its never executed at all :(
        console.log('error!');
        //throw to chain rejection
        throw error;
    });

当函数省略 return 时或 throw语句，它返回 undefined . $q服务创建一个派生的 promise ，解析为 undefined .

诊断 ngResource问题

使用 $resource 诊断问题方法，添加响应拦截器:

userDevices: $resource(api_url+'/requestRegistration/userDevices/:action', {}, {
        registerDevice: {
            method: 'POST',
            params: {
               action: ''
            },
            interceptor: {
                response: function (response) {
                    console.log("registerDevice success");
                    console.log(response.status);
                    return response;
                },
                errorResponse: function (errorResponse) {
                    console.log("registerDevice error");
                    console.log(errorResponse.status);
                    throw errorResponse;
                }
            }
        },
        verify: {
            method: 'POST',

要寻找的另一件事是其他 $http interceptors在应用程序中 转换 省略 的响应扔陈述。