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mysql - 查询以获取一天中基于小时的最多 View

转载 作者:行者123 更新时间:2023-12-01 00:37:04 26 4
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我有表“访客”这些字段是

    id = integer
ip = char
route = char
created_at = timestamp

我想按小时计算分组,我使用了查询

    SELECT * , HOUR(created_at) AS created_hour , COUNT(created_hour)
FROM `visitors` WHERE created_at > DATE(NOW()) GROUP BY created_hour

但我得到这个错误,我可以根据“分组依据”“计数”

SQL query: Documentation

SELECT * , HOUR(created_at) AS created_hour , COUNT(created_hour) FROM `visitors` WHERE created_at > DATE(NOW()) GROUP BY created_hour LIMIT 0, 25

MySQL said: Documentation
#1054 - Unknown column 'created_hour' in 'field list'

最佳答案

COUNT(created_hour) 更改为 COUNT(*)

不要使用WHERE created_at > DATE(NOW()),而是使用WHERE created_at < DATE(NOW())。您查询中的当前 WHERE 条件将强制不返回任何内容。

关于mysql - 查询以获取一天中基于小时的最多 View ,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/46388849/

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