python - 将字符串拆分为多个可能更改的变量

Question

我有一个这样的字符串

b'***************** Winner Prediction *****************\nDate: 2019-08-27 07:00:00\nRace Key: 190827082808\nTrack Name: Mornington\nPosition Number: 8\nName: CONSIDERING\nFinal Odds: 17.3\nPool Final: 37824.7\n'

在 Python 中，我想将此字符串拆分为变量，例如:

Date =  
Race_Key =  
Track_Name =  
Name =  
Final_Odds =  
Pool_Final = 

但是，字符串的格式始终相同，但值始终不同，例如，名称中可能有两个单词，因此需要适用于所有情况。

我已经尝试过:

s = re.split(r'[.?!:]+', pred0)
def search(word, sentences):
       return [i for i in sentences if re.search(r'\b%s\b' % word, i)]

但运气不佳。

Answer 1

您可以拆分字符串并将其解析为如下所示的字典:

s = s.decode() #decode the byte string
n = s.split('\n')[1:-1] #split the string, drop the Winner Prediction and resulting last empty list entry

keys = [key.split(': ')[0].replace(': ','') for key in n] #get keys
vals = [val.split(': ')[1] for val in n] #get values for keys

results = dict(zip(keys,vals)) #store in dict

结果:

Date             2019-08-27 07:00:00
Race Key         190827082808
Track Name       Mornington
Position Number  8
Name             CONSIDERING
Final Odds       17.3
Pool Final       37824.7