javascript - 异步 try/catch 中的多个等待。如何设置一个条件？

Question

我有一个 try/catch 函数，它有多个返回响应的等待函数:

const { data: { req1 } } = await this.props.submitMember(payload1)
const { data: { req2 } } = await this.props.submitSomething(payload2)
const { data: { req3 } } = await this.props.submitThing(payload3)

if (!req.success || !req2.success || !req3.success) {
  return addNotification('Something went wrong.')
}

如何创建一个条件？例如:

const { data: { req1 } } = await this.props.submitMember(payload1)
const { data: { req2 } } = await this.props.submitMember(payload2) // IF SOME VARIABLE IS TRUE, DO NOT RUN THIS REQUEST
const { data: { req3 } } = await this.props.submitMember(payload3)

if (!req.success || !req2.success || !req3.success) {
  return addNotification('Something went wrong.')
}

Answer 1

只需将一个放在条件子句下即可:

const { data: { req1 } } = await this.props.submitMember(payload1);

const { data: { req2 } } =  mustCheck
 ? await this.props.submitMember(payload2)
 : { data: { req2: { success: true } } } // Did not run, did not fail.
;

const { data: { req3 } } = await this.props.submitMember(payload3);

if (!req.success || !req2.success || !req3.success) {
  return addNotification('Something went wrong.')
}

在访问 req2 的结果时，您必须测试 mustCheck，因为如果您没有运行该请求，它可能会合法地未定义。