python - 通过集合列表过滤出现次数

Question

我有一个集合列表:

a = [{'foo','cpu','phone'},{'foo','mouse'}, {'dog','cat'}, {'cpu'}]

预期结果:

我想查看每个单独的字符串，进行计数并以原始格式返回所有 x >= 2:

a = [{'foo','cpu','phone'}, {'foo','mouse'}, {'cpu'}]

我尝试使用列表理解进行循环，但它不适用于集合列表:

a = [k for k in a if a.count(k) >= 2]

Answer 1

from collections import Counter
counter = Counter()
for a_set in a:
    # First we create a counter with counts for all words
    counter.update(a_set)
result = []
for a_set in a:
    for word in a_set:
        if counter[word] >= 2:
            # If any word in any set has a count of 2 or more we append the set
            result.append(a_set)
            break
print(result)