python - 尝试制作一个根据用户输入用 "?"替换辅音单词的 Python 程序

Question

这是我的情况；我正在尝试制作一个Python程序，它接受用户输入并检测任何辅音('B，C，D，F，G，H，J，K，L，M，N，P，Q，R，S，T， V, X, Z') 在用户输入的字符串中，然后用“？”替换所述字母象征。并打印原始单词和找到的辅音的数量。

示例输出:

Please enter a word or zzz to quit: Dramatics
The original word is: dramatics
The word without consonants is: ??a?a?i??
The number of consonants in the word are: 6

我的代码:

 C =  input("Enter A Word (CAPITALS ONLY):")
 S = str(C)
 QUESTIONMARK = str("?")
 chars = str('B, C, D, F, G, H, J, K, L, M, N, P, Q, R, S, T, V, X, Z')
 if any((C in chars) for C in S):
     FINAL = str.replace(QUESTIONMARK,str(S),chars)
     print(FINAL)
 else:
     print('Not Found')

我的输出:

This is what is returned on WING Pro running Python 3.7:

 Enter A Word (CAPITALS ONLY):HELLO
 ?

If there are any solutions to this problem it would be greatly appreciated.

Answer 1

您可以使用以下内容来获取FINAL，这会将每个不是元音的元素替换为“？”:

FINAL = ''.join(e if e in "AEIOU" else "?" for e in S)

您可以对代码进行一些改进。如果您使用的是Python 3，input返回一个字符串，因此您不需要强制转换，您可以直接定义S，如下所示:

S = input("Enter A Word (CAPITALS ONLY):")
QUESTIONMARK = "?"
CONSONANTS = 'BCDFGHJKLMNPQRSTVXZ'

if any((C in CONSONANTS) for C in S):
    FINAL = ''.join(e if e in "AEIOU" else "?" for e in S)
    number_of_consonants = sum(1 for c in S if c in CONSONANTS)
    print(FINAL)
else:
    print('Not Found')

print(f'The original word is: {S}')
print(f'The word without consonants is: {FINAL}')
print(f'The number of consonants in the word are: {number_of_consonants}')

如果需要统计辅音的个数，可以使用下面的

CONSONANTS = 'BCDFGHJKLMNPQRSTVXZ'
number_of_consonants = sum(1 for c in S if c in CONSONANTS)