javascript - 从可能包含函数的对象中获取扁平键

Question

例如，这是我发现的使按键变平的功能

    const keys = flattenKeys({a: { b: 1, c: 1}});

返回

{ 'a.b': 1, 'a.c': 1 }

但是对于这个输入

const keys = flattenKeys({a: { b: 1, c: () => {}}});

它给了我

{ 'a.b': 1 }

正如我们所见，缺少a.c

export const flattenKeys = (obj: Record<string, any> | any[], path: string[] = []) =>
  !isObject(obj) ? { [path.join('.')]: obj } : reduce(obj, (cum, next, key) => merge(cum, flattenKeys(next, [...path, key])), {});

我试图添加 !isObject(obj) && isFunction(obj) ... 但它似乎不起作用

预期输出:

{
 'a.b': 1,
 'a.c': () => {}
}

@编辑:isObject、reduce、merge来自lodash包

Answer 1

将 !isObject(obj) ? 更改为 !isPlainObject(obj) ? 以仅排除普通对象:

const flattenKeys = (obj: Record < string, any > | any[], path: string[] = []) =>
  !_.isPlainObject(obj) ? {
    [path.join('.')]: obj
  } : _.reduce(obj, (cum, next, key) => _.merge(cum, flattenKeys(next, [...path, key])), {});

const keys = flattenKeys({
  a: {
    b: 1,
    c: () => {}
  }
});

console.log(keys);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.15/lodash.min.js"></script>