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jquery - 密码强度不按规则工作

转载 作者:行者123 更新时间:2023-12-01 00:26:42 25 4
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如何更新此规则的以下代码,我尝试过,但似乎总是当我输入 T&5 (UppercaseSymbolNumber) 时很强。

Rule:
at least 9 characters(Any)
two special characters
two numbers
two uppercase letters

There will be two strength type:
1) Week: If not fulfill all Rules.
Then System will not allow for process
2) Good strong password If
All rules fulfill - accept registration

<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title></title>
<style type="text/css">
body
{
font-family: Arial;
font-size: 10pt;
}
#password_strength
{
font-weight: bold;
}
</style>
</head>
<body>
<input type="text" id="txtPassword" />
<span id="password_strength"></span>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<script type="text/javascript">
$(function () {
$("#txtPassword").bind("keyup", function () {
//TextBox left blank.
if ($(this).val().length == 0) {
$("#password_strength").html("");
return;
}

//Regular Expressions.
var regex = new Array();
regex.push("[A-Z]"); //Uppercase Alphabet.
regex.push("[^A-Z$@$!%*#?&0-9]"); //Lowercase Alphabet.
regex.push("[0-9]"); //Digit.
regex.push("[$@$!%*#?&]"); //Special Character.

var passed = 0;

//Validate for each Regular Expression.
for (var i = 0; i < regex.length; i++) {
if (new RegExp(regex[i]).test($(this).val())) {
passed++;
}
}

//Validate for length of Password.
if (passed > 2 && $(this).val().length >= 9) {
passed++;
}

//Display status.
var color = "";
var strength = "";
switch (passed) {
case 0:
case 1:
strength = "Weak";
color = "red";
break;
case 2:
strength = "Good";
color = "darkorange";
break;
case 3:
case 4:
strength = "Strong";
color = "green";
break;
case 5:
strength = "Very Strong";
color = "darkgreen";
break;
}
$("#password_strength").html(strength);
$("#password_strength").css("color", color);
});
});
</script>
</body>
</html>

最佳答案

T&5 匹配 3 个正则表达式 - 大写字母数字特殊字符 - 因此是 强。。如果您需要检查两个个大写字母、两个个数字和两个个特殊字符,请按如下方式修改现有正则表达式:

regex.push("[A-Z][^A-Z]*[A-Z]");
regex.push("[0-9][^0-9]*[0-9]");
regex.push("[@$!%*#?&][^@$!%*#?&]*[@$!%*#?&]");

这些基本上测试您想要需要的字符,然后是除您需要的字符之外的任何 0+ 字符(使用带有 * 量词的否定字符类等效项(反义词类)定义),然后所需字符的第二次出现与初始字符类的另一个实例相匹配。

还有一点:只有在通过 > 2时才检查长度。如果是,您只需增加 passed 即可。您需要对字符串长度添加额外的检查,如果满足要求,则增加 passed

看看下面的示例演示。

$(function() {
$("#txtPassword").bind("keyup", function() {
//TextBox left blank.
var text = $(this).val();
if (text.length == 0) {
$("#password_strength").html("");
return;
}

//Regular Expressions.
var regex = new Array();
regex.push("[A-Z][^A-Z]*[A-Z]"); //Uppercase Alphabet.
regex.push("[^A-Z$@$!%*#?&0-9]"); //Lowercase Alphabet.
regex.push("[0-9][^0-9]*[0-9]"); //Digit.
regex.push("[@$!%*#?&][^@$!%*#?&]*[@$!%*#?&]"); //Special Character.
var passed = 0;

//Validate for each Regular Expression.
for (var i = 0; i < regex.length; i++) {
if (new RegExp(regex[i]).test(text)) {
console.log(text + " passed: " + regex[i]); // Console!
passed++; // Increment on match
}
}

//Validate for length of Password.
if (text.length >= 9) {
console.log(text + " passed length check"); // Console!
passed++; // Increment if length is OK
}

//Display status.
var color = "";
var strength = "";
switch (passed) {
case 0:
case 1:
strength = "Weak";
color = "red";
break;
case 2:
strength = "Good";
color = "darkorange";
break;
case 3:
case 4:
strength = "Strong";
color = "green";
break;
case 5:
strength = "Very Strong";
color = "darkgreen";
break;
}
$("#password_strength").html(strength);
$("#password_strength").css("color", color);
});
});
body {
font-family: Arial;
font-size: 10pt;
}

#password_strength {
font-weight: bold;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="text" id="txtPassword" />
<span id="password_strength"></span>

关于jquery - 密码强度不按规则工作,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37938875/

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