javascript - 过滤其中包含另一个数组的数组

Question

我正在尝试过滤数组

const array = [{
    city: "Fullerton",
    routes: ["Route 1", "Route 2"],
    state: "CA"
}, {
    city: "Long Beach",
    routes: ["Route 3", "Route 4"],
    state: "CA"
}, {
    city: "Huntington Beach",
    routes: "Route 1",
    state: "CA"
}];

通过另一个数组:

const routes = ["Route 1", "Route 3"];

但是，我在过滤原始数组的路由项时遇到了麻烦，因为它有数组和字符串作为其变量。有没有办法使用路由数组并过滤原始数组而不考虑变量类型？

另外，我希望如果您选择其中一条路由，即使数组元素包含更多路由，它也会过滤数组。

Answer 1

如果你想要至少一个路由匹配，你可以组合some和includes:

const routes = ["Route 1", "Route 3"];
const array = [{city: "Fullerton", routes: ["Route 1", "Route 2"], state: "CA"}, {city: "Long Beach", routes: ["Route 3", "Route 4"], state: "CA"}, {city: "Huntington Beach", routes: "Route 1", state: "CA"}];

const filteredArray = array.filter(a =>
  [].concat(a.routes).some(r => routes.includes(r))
)

console.log(filteredArray)

如果您需要完全匹配所有路由，includes 就足够了:

const routes = ["Route 1", "Route 3"];
const array = [{city: "Fullerton", routes: ["Route 1", "Route 2"], state: "CA"}, {city: "Long Beach", routes: ["Route 3", "Route 4"], state: "CA"}, {city: "Huntington Beach", routes: "Route 1", state: "CA"}];

const filteredArray = array.filter(a => routes.includes(a.routes))

console.log(filteredArray)