javascript - 如果字典中的所有其他元素都相同，则对计数求和

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我有一个字典数组，如下所示:

[{name:'v1', count:1}, {name:'v1', count:1}, {name:'v2', count:1}, {name:'v2', count:1}]

如果名称相同，如何将这些计数相加并形成字典，如下所示:

[{name:'v1', count:2}, {name:'v2', count:2}]

Answer 1

解决方案依赖Array.prototype.reduce , Object.entries和 Array.protype.map :

const data = [{name:'v1', count:1}, {name:'v1', count:1}, {name:'v2', count:1}, {name:'v2', count:1}]

const result = Object.entries(data.reduce(
  (acc, { name, count }) => {
    acc[name] = count + (acc[name] || 0)
    return acc
  },
  {}
)).map(([name, count]) => ({ name, count }))

console.log(result)

以下是将同一解决方案分为多个部分，以便于理解:

const data = [{name:'v1', count:1}, {name:'v1', count:1}, {name:'v2', count:1}, {name:'v2', count:1}]

const r1 = data.reduce(
  (acc, { name, count }) => {
    acc[name] = count + (acc[name] || 0)
    return acc
  },
  {}
)
console.log(r1)

const r2 = Object.entries(r1)
console.log(r2)

const r3 = r2.map(([name, count]) => ({ name, count }))
console.log(r3)