python - 将学生数据存储在Python列表中以获取百分比

Question

import re
import os
import sys
class Marks:
    def __init__(self):
        self.marks = []
        self.marks_file = '/root/projectpython/mark.txt'
    def loadAll(self):
        file = open(self.marks_file, 'r')
        for line in file.readlines():
            name,math,phy,chem = line.strip().split()
            name=name
            math=int(math)
            phy=int(phy)
            chem=int(chem)
            self.marks=[name,math,phy,chem]
            print(self.marks)
        file.close()

    def percent(self):
        dash = '-' * 40
        self.loadAll()
        for n in self.marks:
            print(n)

Book_1 = Marks()
Book_1.percent()

输出:-

['gk', 50, 40, 30]
['rahul', 34, 54, 30]
['rohit', 87, 45, 9]
rohit
87
45
9

但我想以表格格式打印所有值，它只显示最后一条记录。使用列表存储学生数据姓名和分数是否正确？

Answer 1

这里的问题是读取的行

self.marks=[name,math,phy,chem]

每次读取标记时，这都会重新初始化列表

改为使用:

self.marks.append([name,math,phy,chem])