jQuery 盒子问题

Question

我正在尝试使用 jQuery 解决矩形问题。基本上，我有 3 个方形盒子，固定在一个更大的盒子内。

我知道较大的框的最大宽度为 500px。我不知道 1、2 或 3 的大小是多少 - 但我知道它们的纵横比可以改变，并且它们必须按比例适合盒子。

我如何始终确保无论什么形状 - 3 个矩形在 500px 盒子内始终按比例调整大小？

Answer 1

解出方程组后，我相信以下说法正确。

w  = Overall width (500)
h  = Overall height
w1 = Width of B1
h1 = Height of B1
w2 = Width of B2
h2 = Height of B2
w3 = Width of B3
h3 = Height of B3
a1 = Aspect ratio of B1 (width/height)
a2 = Aspect ratio of B2 (width/height)
a3 = Aspect ratio of B3 (width/height)

w1 = (500/a2 + 500/a3) / (1/a1 + 1/a2 + 1/a3)

500 px、a1、a2 和 a3 是已知的。求解 w1，然后求解 w2 和 w3。使用a1、a2和a3确定h1、h2和h3。

我相信你的算法应该是:

1: Find w1
w1 = (500/a2 + 500/a3) / (1/a1 + 1/a2 + 1/a3)

2: Find w2 and w3
w1+w2 = 500
w1+w3 = 500

3: Determine ideal h1, h2, and h3 via aspect ratio
h1 = w1/a1
h2 = w2/a2
h3 = w3/a3

4: Best-Fit h1, h2, and h3
h = h1 = max(h2+h3, h1)
h2 = h2 + ((h - (h2+h3))/2)
h3 = h3 + ((h - (h2+h3))/2)

这是我遵循的步骤

Eq1: w1/a1 = h1                              [aspect ratio]                
Eq2: h1 = (h2 + h3)                          [see diagram]
Eq3: h2 = w2/a2                              [aspect ratio]  
Eq4: h3 = w3/a3                              [aspect ratio]  
Eq5: w2 = 500 - w1                           [see diagram]
Eq6: w3 = 500 - w1                           [see diagram]

w1/a1 = h1                                   [Eq1]
w1/a1 = (h2 + h3)                            [Eq2]
w1/a1 = (w2/a2 + w3/a3)                      [Eq3, Eq4]
w1/a1 = ((500 - w1)/a2 + (500 - w1)/a3)      [Eq5, Eq6]

w1/a1 = 500/a2 - w1/a2 + 500/a3 - w1/a3
w1/a1 + w1/a2 + w1/a3 = 500/a2 + 500/a3 
w1 * (1/a1 + 1/a2 + 1/a3) = 500/a2 + 500/a3 
w1 = (500/a2 + 500/a3) / (1/a1 + 1/a2 + 1/a3)