python - 从带有冒号的行中解析单词(简单的初学者作业)

Question

使用“travel_plans.txt”中存储的数据创建一个名为“目的地”的列表。列表的每个元素都应包含文件中的一行，其中列出了一个国家/地区以及该国家/地区内的城市。

“travel_plans.txt”包含:

This summer I will be travelling.
I will go to...
Italy: Rome
Greece: Athens
England: London, Manchester
France: Paris, Nice, Lyon
Spain: Madrid, Barcelona, Granada
Austria: Vienna
I will probably not even want to come back!
However, I wonder how I will get by with all the different languages.
I only know English!

到目前为止，我已经编写了以下内容:

with open("travel_plans.txt","r") as fileref:
    for line in fileref:
        row = line.strip().split()
        if ":" in row[0]:
            destination = row
            print(destination)

是否有更好的方法来获得相同的输出？

Answer 1

destination = []
with open("travel_plans.txt","r") as fileref:
    for line in fileref:
        row = line.strip()
        if ":" in row:
            destination.append(row)
print(destination)

对于一个小文件，超过这个值可能就有点过分了。

你可以让它变得更短。

destination = [line.strip() for line in fileref if ":" in line]
print(destination)