javascript - 在 React Native 中函数成功后，如何立即启动新函数

Question

我想在一个函数完成后运行一个函数，并将一些数据传递给第二个函数。我分别测试了这两个功能，它们都有效。但我想在第一个完成后立即启动第二个

这是我的代码，但第二个函数无法正常运行。

const ChargeCard = (dispatch) => ({
    cardNumber,
    expiryMonth,
    expiryYear,
    cvc,
    email,
    amountInKobo,
    id
}) => {

    try {
        RNPaystack.chargeCard({
            cardNumber: cardNumber,
            expiryMonth: expiryMonth,
            expiryYear: expiryYear,
            cvc: cvc,
            email: email,
            amountInKobo: amountInKobo * 100

        })
            .then(response => {

                if (response) {
                    setBasic({ id }) //the function to run if this is successful
                }                
            })

    } catch {

        dispatch({
            type: "ADD_ERROR",
            payload:
                "Something went wrong during payment, please try again, don't worry you have not been charged."
        });    
    }

};

这个函数我想立即运行即成功；

const setBasic = () => async ({ id }) => {
    const Basic = 1
    const response = await appApi.put(`/usersub/${id}`, { Basic });
    if (response) {
        console.log(response.data)
    }
}

Answer 1

将第二个函数更改为:

const setBasic = async ({ id }) => {
    const Basic = 1
    const response = await appApi.put(`/usersub/${id}`, { Basic });
    if (response) {
        console.log(response.data)
    }
}

您将其定义为:

const setBasic = () => async ({ id }) => {

但是你用以下方式调用它:

 setBasic({ id })