python - 如何获得学期平均分

Question

我的代码将采用成绩图例和成绩数，然后返回它的值。除了学期平均分外，我一切都好。以下是计算学期平均分的公式:

homework average * 0.2 + quiz average * 0.2 + project average * 0.6.

我的代码适用于家庭作业平均数、测验平均数和项目平均数，但不适用于学期平均数。这是我写的:

def get_header():  
    gb_data = open('gb_data.txt','r')
    header = gb_data.readline()
    return header.strip()

def get_content():  
    gb_data = open('gb_data.txt','r')
    content = gb_data.readlines()
    del content[0]
    return content

hw_pos = []
project_pos = []
quiz_pos =  []

header_list = get_header()
header_list = header_list.split(", ")
header_list_index = enumerate(header_list)
for index, target in header_list_index:
    if target == "hw":
        hw_pos.append(index)
    elif target == "quiz":
        quiz_pos.append(index)
    elif target == "project":
        project_pos.append(index)

content_list = get_content()

avg_dict = {}

for element in content_list:
    element = element.strip().split(", ")

    name = element[0] + ', ' + element[1]
    hw_avg = sum([int(element[i]) for i in hw_pos]) / len(hw_pos)
    quiz_avg = sum([int(element[i]) for i in quiz_pos]) / len(quiz_pos)
    project_avg = sum([int(element[i]) for i in project_pos]) / len(project_pos)
    sem_avg = hw_avg * 0.2 + quiz_avg * 0.2 + project_avg * 0.6
    avg_dict.update({name:(hw_avg, quiz_avg, project_avg, sem_avg)})


f = open('avg.txt', 'w')
for name, avg in avg_dict.items():
  dataline = name + ": hw avg = " + str(round(avg[0], 2)) + ", quiz avg = " + str(round(avg[2], 2)) + ", proj avg = " + str(round(avg[1], 2)) + ", sem avg = " + str(round(avg[2], 2)) + "\n"
  f.write(dataline)

f.close()

这是我输入的一个示例:

last, first, hw, hw, project, quiz, hw, hw, hw, quiz, hw, hw, project
Cat, Figaro, 57, 58, 71, 93, 56, 86, 90, 99, 55, 99, 88

顶行是图例，所以忽略它，我的代码会处理它以下是应该返回的内容:

Cat, Figaro: hw avg = 71.57, quiz avg = 96.0, proj avg = 79.5, sem avg = 81.21

这是我实际得到的结果:

Cat, Figaro: hw avg = 71.57, quiz avg = 96.0, proj avg = 79.5, sem avg = 96.0

我想让它们完全匹配，精确到每个字符。我只需要知道如何正确舍入它。这不是家庭作业，只是一个更好地理解文件的项目，我非常接近了!顺便说一句，我叫斯嘉丽，请帮忙!!!

Answer 1

这行有一个拼写错误:

dataline = name + ": hw avg = " + str(round(avg[0], 2)) + ", quiz avg = " + str(round(avg[2], 2)) + ", proj avg = " + str(round(avg[1], 2)) + ", sem avg = " + str(round(avg[2], 2)) + "\n"

应该是

dataline = name + ": hw avg = " + str(round(avg[0], 2)) + ", quiz avg = " + str(round(avg[1], 2)) + ", proj avg = " + str(round(avg[2], 2)) + ", sem avg = " + str(round(avg[3], 2)) + "\n"

相反。计算没问题，只是输出困惑了(您打印了 0, 2, 1, 2 而不是 0, 1, 2, 3)。为了防止将来出现类似的错误，也许可以看看 Pandas 及其列名？在这种情况下，Pandas 可能有点大材小用，但它是基于表格的计算的一个非常强大的工具。