python - 如何知道函数方法装饰器中的类名称？

Question

我有一个简单的时间标记装饰器用于功能:

def dec_timemark(f):
    def tmp(*args, **kwargs):
        sys.stdout.write(strftime("%d.%m.%Y %H:%M:%S") + ' ' + f.__name__ +
                                                         ' begin' + "\n" )
        res = f(*args, **kwargs)
        sys.stdout.write(strftime("%d.%m.%Y %H:%M:%S") + ' ' + f.__name__ +
                                                         ' end' + "\n"     )
        return res
    return tmp

典型用法:

class Task():
    @dec_timemark
    def make_torrent():
        sleep(10)

但是如何添加类的装饰器名称呢？ (不记录:“make_torrent begin”，而是“Task.make_torrent begin”)？

Answer 1

假设装饰例程作为方法调用，您可以从 self 参数中提取类名:

def dump(f):
    def decorated(self, *args, **kwargs):
        print 'Class: {0}'.format(self.__class__.__name__)
        print 'Args passed to decorated function: {0}'.format(args)
        print 'Keyword args passed to decorated function: {0}'.format(kwargs)
        return f(self, *args, **kwargs)
    return decorated

class Test(object):
    """
    >>> Test().test('arg1', 'arg2', kwarg1='kwval1')
    Class: Test
    Args passed to decorated function: ('arg1', 'arg2')
    Keyword args passed to decorated function: {'kwarg1': 'kwval1'}
    """
    @dump
    def test(*args, **kwargs):
        pass