python - 如何在Python中获取循环范围内的值并在循环外使用它

Question

有人可以帮助我思考解决这个问题的方法吗？在下面的代码中，我将获取一个列表并打开所有 .log 和 .txt 文件，以便在它们中搜索特定字符串。在最里面的 for 循环中有一个 if 和 else 语句，用于确定是否找到字符串。我想计算字符串匹配的文件数量...，并以某种方式将其传递给第三个(最后一个)for循环并显示...(例如匹配的文件:4)。我仍在学习 python，所以我不知道所有可以加快这一努力的不同结构。我确信这是一个直接的问题，但除了死记硬背的反复试验之外，我已经用尽了我所知道的一切。谢谢!

...

for afile in filelist:
    (head, filename) = os.path.split(afile)
    if afile.endswith(".log") or afile.endswith(".txt"):
        f=ftp.open(afile, 'r')
        for i, line in enumerate(f.readlines()):
            result = regex.search(line)
            if result:
                ln = str(i)
                pathname = os.path.join(afile)
                template = "\nLine: {0}\nFile: {1}\nString Type: {2}\n\n"
                output = template.format(ln, pathname, result.group())
                hold = output
                print output
                ftp.get(afile, 'c:\\Extracted\\' + filename)
                temp.write(output)
                break
        else:
            print "String Not Found in: " + os.path.join(afile)
            temp.write("\nString Not Found: " + os.path.join(afile))

        f.close()
for fnum in filelist:
    print "\nFiles Searched: ", len(filelist)
    print "Files Matched: ", count
    num = len(filelist)

    temp.write("\n\nFiles Searched: " + '%s\n' % (num))
    temp.write("Files Matched: ") # here is where I want to show the number of files matched
    break

Answer 1

这个怎么样:

count = 0
for afile in filelist:
    (head, filename) = os.path.split(afile)
    if afile.endswith(".log") or afile.endswith(".txt"):
        f=ftp.open(afile, 'r')
        for i, line in enumerate(f.readlines()):
            result = regex.search(line)
            if result:
                count += 1
                ln = str(i)
                pathname = os.path.join(afile)
                template = "\nLine: {0}\nFile: {1}\nString Type: {2}\n\n"
                output = template.format(ln, pathname, result.group())
                hold = output
                print output
                ftp.get(afile, 'c:\\Extracted\\' + filename)
                temp.write(output)
                break
        else:
            print "String Not Found in: " + os.path.join(afile)
            temp.write("\nString Not Found: " + os.path.join(afile))

        f.close()
for fnum in filelist:
    print "\nFiles Searched: ", len(filelist)
    print "Files Matched: ", count
    num = len(filelist)

    temp.write("\n\nFiles Searched: " + '%s\n' % (num))
    temp.write("Files Matched: "+str(count)) # here is where I want to show the number of files matched
    break

计数从 0 开始，并随着每个匹配的文件而递增。