javascript - 如何解决 jQuery 错误 "$ not found error"问题？

Question

主窗口

// some javascript
//some html
//here ajax-call to load all divs
//all divs hidden by default
//based on user choice(from select option), show selected group of divs
//click any shown div to call corresponding popup

弹出窗口

//edit contents of that div.
//on close i need
1. refresh main window to load all divs
2. select the previously selected user option(from select option)
3. show corresponding divs only
4. most important is i have to give the user the main page,
   where they clicked the div before(not the page starting always!)

我尝试过，但留下了“$未找到错误”。有任何想法吗..？有什么建议吗？

这是主窗口

     <script type="text/javascript" src="jquerymin.js"></script>
        <script type="text/javascript">
        var visible_status=0;
        function selectFn(sno){
        if(sno==1){
                $('#id2').hide();
                $('#id1').show();
                visible_status=1;
        }else if(sno==2){
                $('#id2').show();
                $('#id1').show();
                visible_status=2;
        }
        }

        function popitup(url) {
            newwindow=window.open(url+'?parent_status='+visible_status,'name');
            if (window.focus) {newwindow.focus();}
                return false;
        }
        </script>
        <select name='optionw' 
        onchange="selectFn(this.options[this.selectedIndex].value);">
        <option value="">Select</option>
        <option value="1">Div1</option>
        <option value="2">All</option>
        </select>
        <div id='id1' style="display:none;">DIV1</div><!--by ajax i am loading-->
        <div id='id2' style="display:none;">DIV2</div><!--these divs-->
        <button onclick="popitup('popup.php');">popUp</button><br><!--and these-->

弹出窗口

<script type="text/javascript" src="jquerymin.js"></script>
    <script type="text/javascript">
    var parent_status='<? echo $_GET[parent_status];?>';

    function closePopup() {
        window.opener.history.go(0);
        //alert('going to call parent selectFn('+parent_status+')');
        window.opener.selectFn(parent_status);
        self.close();
    }
    </script>

...Here  editing a part of the main page content...
<input type=button value=close_popup onclick="closePopup();">

如果我删除 closePopup 函数中的注释，它会按预期工作。任何帮助使其在没有命令行的情况下工作。

Answer 1

我建议您可能没有正确链接到 jQuery 库或者以错误的顺序链接。您能否提供有关您所要求的更多详细信息？您希望代码执行此操作，还是只是询问未找到 jQuery 对象？