python - python中压缩文件夹的完整文件路径

Question

我有以下代码试图获取完整的文件路径(包括文件夹):

import zipfile
import os
import sys

zipped_files_dir = 'Z:\Dev\some_files'

def get_folder_names():
    path_list = []
    for folder_name in os.listdir(zipped_files_dir):
        path_list.append(folder_name)
    return path_list

def get_folder_directories(folder_list):
    for folder in folder_list:
        pathname = os.path.abspath(folder)
        print(pathname)

def main():
    get_folder_directories(get_folder_names())

>>>Z:\Dev\new_folder.zip  

我的问题是返回的目录中应该有“\some_files\new_folder.zip”。有什么想法吗？

谢谢!

Answer 1

您可以在get_folder_directories函数中使用os.path.join(zipped_files_dir,folder):

import zipfile
import os
import sys

zipped_files_dir = 'Z:\Dev\some_files'

def get_folder_names():
    path_list = []
    for folder_name in os.listdir(zipped_files_dir):
        path_list.append(folder_name)
    return path_list

def get_folder_directories(folder_list):
    for folder in folder_list:
        pathname = os.path.abspath(os.path.join(zipped_files_dir, folder))
        print(pathname)

def main():
    get_folder_directories(get_folder_names())

<小时/>

或者，get_folder_names()中的path_list.append(os.path.join(zipped_files_dir,folder_name)):

import zipfile
import os
import sys

zipped_files_dir = 'Z:\Dev\some_files'

def get_folder_names():
    path_list = []
    for folder_name in os.listdir(zipped_files_dir):
        path_list.append(os.path.join(zipped_files_dir, folder_name))
    return path_list

def get_folder_directories(folder_list):
    for folder in folder_list:
        pathname = os.path.abspath(folder)
        print(pathname)

def main():
    get_folder_directories(get_folder_names())