python - 如果我使用 Dicts 名称创建变量，如何在 dict 中查找值？

Question

用代码更容易解​​释:

#test data
Day1={  
      'data1':0,
      'data2':   1,
      'data3':    2,
      'data4':    3,
      'data5':    4,
      'data6':    5,
      'data7':    4,
      'data8':    3,
      'data9':    2,
      'data10':    1}

Day2= {  
       'data1':    2,
       'data2':    3,
       'data3':    4,
       'data4':    5,
       'data5':    6,
       'data6':    6,
       'data7':    7,
       'data8':    6,
       'data9':    4,
       'data10':    3}

Day3= {    
       'data1':    2,
       'data2':    4,
       'data3':    5,
       'data4':    6,
       'data5':    7,
       'data6':    6,
       'data7':    8,
       'data8':    6,
       'data9':    5,
       'data10':    4}

Day4= {   
       'data1':    2,
       'data2':    4,
       'data3':    5,
       'data4':    6,
       'data5':    7,
       'data6':    6,
       'data7':    6,
       'data8':    8,
       'data9':    5,
       'data10':    4}

AllData= {'Day1':Day1,'Day2':Day2,'Day3':Day3,'Day4':Day4}


#Number of items in AllData dictionary
AllDataSize = len(AllData)
CurrentDayCounter=0

while CurrentDayCounter < AllDataSize:
    CurrentDayCounter=CurrentDayCounter+1
    CurrentDay = 'Day%s' % (CurrentDayCounter)
    #print AllData[CurrentDay]
    #add the nodes
    for day in AllData[CurrentDay]:
        print CurrentDay
        day = "%s" % (day)
        print CurrentDay[day] #does not work gives an error: TypeError: string indices must be integers, not str
        print CurrentDay[1] #works by providing a result 'a', which is the second letter in Day
        #print 'For ', CurrentDay, ' subgroup ', day,' contains ', CurrentDay[day], ' has been added to graph.'
        dayName =  "%s-%s" % (CurrentDay, Day1[day])
        #Do not create edges if its the first day
        if CurrentDay != "Day1":
            yesterday = CurrentDayCounter - 1
            print 'today is ', CurrentDayCounter, ' and yesterday is ', yesterday

当我打印 CurrentDay[day] 时，出现错误: TypeError: stringindexs Must be integers, not str 但 CurrentDay[1] 给出的结果是(这是变量的中间字母。我想使用该变量来搜索字典，而不是拉出字母位置。

我怀疑我这样做是完全错误的，那么有正确的方法吗？

谢谢!附注抱歉，代码很糟糕，我只是在玩networkx，我想我删除了对它的所有引用，但如果我错过了任何内容，请忽略它。

Answer 1

第 (65) 行应该是:

print AllData[CurrentDay][day] 

出现错误消息的原因是 print CurrentDay[day] 打印字符串 CurrentDay 中的第 day 个字符