python - 如何解析目录中的每个 html 文件中的图像？

Question

我有一个充满 html 文件的目录，每个文件中都有一张牛皮癣患者的临床图像。我想打开每个文件，找到图像，并将其保存在同一目录中。

import os, os.path
import Image
from BeautifulSoup import BeautifulSoup as bs

path = 'C:\Users\gokalraina\Desktop\derm images'

for root, dirs, files in path:
    for f in files:
        soup = bs(f)
        for image in soup.findAll("img"):
            print "Image: %(src)s" % image
            im = Image.open(image)
            im.save(path+image["src"], "JPEG")

我收到此错误:

 Traceback (most recent call last):
   File "C:\Users\gokalraina\Desktop\modfile.py", line 7, in <module>
     for root, dirs, files in path:
 ValueError: need more than 1 value to unpack

即使在谷歌上搜索错误后，我也不知道出了什么问题或者我是否正确地执行了此操作。请记住，我是 python 新手。

编辑:对程序进行建议的更改后，我仍然收到错误:

  Traceback (most recent call last):
  File "C:\Users\gokalraina\Desktop\modfile.py", line 25, in <module>
    im = Image.open(image)
  File "C:\Python27\lib\site-packages\PIL\Image.py", line 1956, in open
    prefix = fp.read(16)
 TypeError: 'NoneType' object is not callable

这是修改后的代码(感谢 nightcracker)

 import os, os.path
 import Image
 from BeautifulSoup import BeautifulSoup as bs

 path = 'C:\Users\gokalraina\Desktop\derm images'

 for root, dirs, files in os.walk(path):
    for f in files:
       soup = bs(open(os.path.join(root, f)).read())
       for image in soup.findAll("img"):
          print "Image: %(src)s" % image
          im = Image.open(image)
          im.save(path+image["src"], "JPEG")

Answer 1

您需要更改此行:

for root, dirs, files in path:

至

for root, dirs, files in os.walk(path):

另请注意，文件是文件名称，而不是对象，因此这将是您的固定代码:

import os, os.path
import Image
from BeautifulSoup import BeautifulSoup as bs

path = 'C:\Users\gokalraina\Desktop\derm images'

for root, dirs, files in os.walk(path):
    for f in files:
        soup = bs(open(os.path.join(root, f)).read())
        for image in soup.findAll("img"):
            print "Image: %(src)s" % image
            im = Image.open(image)
            im.save(path+image["src"], "JPEG")