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python - 将参数作为 HTML 属性传递

转载 作者:行者123 更新时间:2023-11-30 23:41:29 25 4
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我正在尝试使用 Bottle 和 HTML 来测试 HTTP GET 和 POST。我编写了这段代码,要求用户输入颜色名称作为参数,如果它存在于预定义列表中,那么它应该打印找到并显示颜色。但我不知道如何通过争论。如果我尝试橙色、红色等默认值,效果很好。

from bottle import*
import socket

@error(404)
def error404(error):
return '<p align=center><b>Sorry, a screw just dropped.Well, we are hoping to find it soon.</b></p>'

@get('/New/rem_serv/:arg')
def nextstep(arg):
_colorlist=['Red','Green','Blue','Yellow','Orange','Black','White']

if arg in _colorlist:
return "Found the same color \n","<p style='font-weight:bold; text-align:center; background-color:arg;'>" + str(arg)
else:
return error404(404)

addrIp = socket.getaddrinfo(socket.gethostname(), None)
addrIp = addrIp[0][4][0]
run(host=addrIp, port=80)

最佳答案

你可以尝试这样的事情:

@app.route('/New/rem_serv/:arg')
@view('template.tpl')
def nextstep(arg):
_colorlist=['Red','Green','Blue','Yellow','Orange','Black','White']
if arg in _colorlist:
context = {'result': "Found the same color %s" % arg}
else:
context = {'result': "color not found"}
return (context)

你也可以尝试这个:

from bottle import Bottle, run, view, request

app = Bottle()

@app.route('/New/rem_serv/')
@view('template.tpl')
def nextstep():
"""
get the color from the url
http://127.0.0.1:8080/New/rem_serv?color=xxx
"""
_colorlist=['Red','Green','Blue','Yellow','Orange','Black','White']
if arg in _colorlist:
context = {'result': "Found the same color %s" % request.params.color}
else:
context = {'result': "color not found"}
return (context)

那么剩下的就是template/html/css的问题了

关于python - 将参数作为 HTML 属性传递,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11988232/

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