python - 如何从 url 中带有冒号 ":"的 url 获取 htmlcode？

Question

我已经成功使用 python 和 urllib2 模块检索常规网页中的 html 代码。

但是当我尝试将它与带有冒号的网页一起使用时，它不起作用。此代码:

f = urllib2.urlopen("http://http://gulasidorna.eniro.se/hitta:svenska+kyrkan/")
htmlcode = f.read()
print htmlcode

以下代码生成此错误消息。

File "/Users/jonathan/Documents/Dropbox/Python/eniro.py", line 137, in <module>
  f = urllib2.urlopen("http://http://gulasidorna.eniro.se/hitta:svenska+kyrkan/")
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 126, in urlopen
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 394, in open
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 412, in _open
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 372, in _call_chain
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 1199, in http_open
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 1140, in do_open
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/httplib.py", line 693, in _init_
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/httplib.py", line 718, in _set_hostport
httplib.InvalidURL: nonnumeric port: ''

Answer 1

这应该可行，网址开头有一个额外的 http://:

f = urllib2.urlopen("http://gulasidorna.eniro.se/hitta:svenska+kyrkan/")
htmlcode = f.read()
print htmlcode