python - 如何根据条件将列表转换为三个列表并放入字典中

Question

我有这样的列表

mylist = [student_number , student_age , student_marks , subject_name , subject_marks, subject_date , ass_name , ass_number]

我想要类似的东西

   list_student = [student_number , student_age , student_marks]
   list_subject = [subject_name , subject_marks, subject_date]
   list_ass     = [ass_name , ass_number]

以便它与下划线之前的文本匹配，将其作为字典的键

我想将其转换为字典，以便我可以访问类似的内容

 for a AllList['student']:
           Student stuff

编辑:列表元素可以按任何顺序

Answer 1

我会这样做:

# Build dictionary with prefix:list pairs
targets = {
    'student_': [],
    'subject_': [],
    'ass_': []
}

for i in mylist:
    # Try to find matching prefix
    for prefix in targets:
        if i.startswith(prefix):
            targets[prefix].append(i)
            break

这将允许您轻松添加更多前缀并且不关心顺序。

假设(值是字符串):

mylist = ['student_number', 'student_age', 'student_marks', 'subject_name',
          'subject_marks', 'subject_date' , 'ass_name' , 'ass_number' ]

你会得到这样的结果:

>>> for i in targets: print( i, targets[i])
...
ass_ ['ass_name', 'ass_number']
student_ ['student_number', 'student_age', 'student_marks']
subject_ ['subject_name', 'subject_marks', 'subject_date']