php - 奇怪的 MYSQL 错误

Question

我在文件中的查询在 php 文件中看起来像这样:

SELECT
            p.products_id as v_products_id,
            p.products_model as v_products_model,
            p.products_image as v_products_image,
            p.products_price as v_products_price,
            p.products_sku as v_products_sku,
            p.products_upc as v_products_upc,
            p.products_weight as v_products_weight,
            p.products_date_added as v_date_added,
            p.products_date_available as v_date_avail,
            p.products_tax_class_id as v_tax_class_id,
            p.products_quantity as v_products_quantity,
            p.manufacturers_id as v_manufacturers_id,
            subc.categories_id as v_categories_id
            FROM
            zen_products as p,
            zen_categories as subc,
            zen_products_to_categories as ptoc
            WHERE
            p.products_id = ptoc.products_id AND
            p.products_model = 'M150XN05' AND
            ptoc.categories_id = subc.categories_id

我收到一个返回错误:MySQL 错误 1054:“字段列表”中的未知列“p.produc1925ts_tax_class_id”执行时:

SELECT
            p.products_id as v_products_id,
            p.products_model as v_products_model,
            p.products_image as v_products_image,
            p.products_price as v_products_price,
            p.products_sku as v_products_sku,
            p.products_upc as v_products_upc,
            p.products_weight as v_products_weight,
            p.products_date_added as v_date_added,
            p.products_date_available as v_date_avail,
                    -- extra 1925 here
            p.produc1925ts_tax_class_id as v_tax_class_id,
            p.products_quantity as v_products_quantity,
            p.manufacturers_id as v_manufacturers_id,
            subc.categories_id as v_categories_id
            FROM
            zen_products as p,
            zen_categories as subc,
            zen_products_to_categories as ptoc
            WHERE
            p.products_id = ptoc.products_id AND
            p.products_model = 'M150XN05' AND
            ptoc.categories_id = subc.categories_id

这是怎么回事，额外的“1925”是如何被放置到选择的中间的？我不知所措，我已经尝试了所有我能想到的可能导致此问题的方法。

完整代码在这里http://pastebin.com/embed_iframe.php?i=Q2RHT00W

Answer 1

MySQL 不会像您期望的那样解析隐式连接。

(引用已删除，因为它是错误的段落，但这是我以前遇到过的已知错误!)

为避免混淆，我建议改用显式连接:

zen_products as p,
zen_categories as subc,
zen_products_to_categories as ptoc
WHERE
p.products_id = ptoc.products_id AND
p.products_model = 'M150XN05' AND
ptoc.categories_id = subc.categories_id

成为

zen_products as p
JOIN zen_products_to_categories as ptoc
    ON p.products_id = ptoc.products_id
JOIN zen_categories as subc
    ON ptoc.categories_id = subc.categories_id
WHERE p.products_model = 'M150XN05'