python - 将列表中的值分开以形成坐标对

Question

下面是我当前的代码。

import csv
def function():

    latitude = []
    longitude = []
    with open('data.csv', 'rU') as input: #
          dL= list(csv.reader(input))
          sL = [row[4] for row in dL[1:]]
          longitude.append(sL)
          sL1 = [row[3] for row in dL[1:]]
          latitude.append(sL1)

    print latitude
    print longitude

    print
    for i in range(0, len(latitude)):
        print "Co-ordinates (" + str(latitude[i]) + "," + str(longitude[i]) + ")"

function()

是的，所以我的输出产生了这个

[['-20.71', '-20.73', '-20.88', '-20.78', '-20.76', '-20.68', '-20.95', '-21.06', '-21.05', '-20.9']]
[['116.77', '116.75', '116.67', '117.15', '117.16', '117.19', '117.37', '117.44', '116.26', '117.64']]

Co-ordinates (['-20.71', '-20.73', '-20.88', '-20.78', '-20.76', '-20.68', '-20.95', '-21.06', '-21.05', '-20.9'],['116.77', '116.75', '116.67', '117.15', '117.16', '117.19', '117.37', '117.44', '116.26', '117.64'])

这显示了我想要生成的列表。

我想要做的是产生如下所示的输出

Co-ordinates (-20.71,116.77)
Co-ordinates (-20.73, 116.75) 

对于所有坐标对依此类推。

有什么方法可以获得我想要的输出坐标吗？

Answer 1

1. 您想使用extend而不是append。
2. zip(纬度，经度)

再想一想，您可以对 dL[1:]] 中的行执行longitude = [row[4] for row in dL[1:]]。您不需要扩展(或附加或初始化)任何内容。

更好:

with open('data.csv', 'rU') as infile:
      dl = list(csv.reader(infile))
lat_long = [tuple(row[3:5]) for row in dl[1:]]
for (lat, lng) in lat_long:
    print "Co-ordinates ({0}, {1})".format(lat, lng)