来自两个表的MYSQL QUERY总和

Question

嘿，我在使用以下 Mysql 查询时遇到了一些麻烦，我如何从 team_stats 表而不是 driver_stats 表中计算 SUMS(这是计算点，查询中的第 5 和第 6 总和)与现在 team_id = 3 的条件相同。我所需要的只是将这些计算从 driver_stats 表交换到 team_stats 表，我遇到的问题是当我尝试这样做时，计算量太高了不只是为了 where team_id = '3' 或任何数字。

如果有任何帮助，我们将不胜感激。

SELECT       t.teamname,
             t.value,
             SUM(IF(qual_pos = '1', 1,0)) AS poles,
             SUM(IF(race_pos <= '3', 1,0)) AS podiums,
             SUM(IF(race_pos = '1', 1,0)) AS victories,
             SUM(overtakes) AS overtakes,
             SUM(CASE
               WHEN s.track_id = (SELECT MAX(track_id) FROM driver_stats) THEN
                 points
               ELSE
                 0
             End) AS lastracepoints,

             # CHANGE THIS SUM AND THE SUM ABOVE TO CALCULATE
             # the points column in the tale named TEAM_STATS
             # but with the same restrictions as now,
             # only where team_id = 3
             SUM(points) AS points 

FROM         driver_stats s
  LEFT JOIN  drivers d
  ON         d.drivers_id = s.drivers_id
  LEFT JOIN  teams t
  ON         d.team_id = t.team_id
WHERE        d.team_id = 3

Answer 1

在特殊情况下，MySQL 可以让您在不定义 group by 子句的情况下使用聚合(sum)，但这不是典型的，对您不起作用。

Is it possible to use Aggregate function in a Select statment without using Group By clause?

我还没有通过 try 测试过这个:

SELECT       t.teamname,
             t.value,
             SUM(IF(qual_pos = '1', 1,0)) AS poles,
             SUM(IF(race_pos <= '3', 1,0)) AS podiums,
             SUM(IF(race_pos = '1', 1,0)) AS victories,
             SUM(overtakes) AS overtakes,
             SUM(CASE
               WHEN s.track_id = (SELECT MAX(track_id) FROM driver_stats) THEN
                 points
               ELSE
                 0
             End) AS lastracepoints,
             SUM(points) AS points 

FROM         drivers d
  INNER JOIN  driver_stats s
  ON         d.drivers_id = s.drivers_id
  AND         d.team_id = 3
  LEFT JOIN  teams t
  ON         d.team_id = t.team_id
GROUP BY
    teamname,
    `value`