python - Django ModelAdmin 额外输入字段不是来自模型

Question

我正在尝试向我拥有的模型的 admin.ModelAdmin 添加额外的输入，以便在另一个输入发生更改时可以记录一些可选文本。

我无法将自定义ModelForm识别为名称“EquipmentAdmin”未定义。我尝试了几种不同的导入方式，但我认为我一定错过了一些明显的东西。感觉 EquipmentAdmin 和 EquipmentAdminForm 之间存在循环引用，因为它们都在代码中包含对彼此的引用。

我已经创建了 Django 应用程序 Flightdeck 并将它们全部放在同一个文件夹中；

models.py

from django.db import models

class Location(models.Model):
    name = models.CharField(max_length=45)

class Equipment(models.Model):
    unit_id = models.CharField(max_length=45)
    located = models.ForeignKey(Location)
    located_from = models.DateField()

class EquipmentLocationHistory(models.Model):
    unit = models.ForeignKey(Equipment)
    located = models.ForeignKey(Location)
    start = models.DateField()
    end = models.DateField()
    change_reason = models.CharField(max_length=45)

admin.py

from django.contrib import admin

from flightdeck.models import *
from flightdeck.forms import EquipmentAdminForm

class EquipmentAdmin(admin.ModelAdmin):
    form = EquipmentAdminForm

    def save_model(self, request, obj, form, change):
        if 'located' in form.changed_data:
            try:
                old = Equipment.objects.get(unit_id=obj.unit_id)
            except Equipment.DoesNotExist:
                old = None

        if old:
            if 'located' in form.changed_data:
                located_history = EquipmentLocationHistory(unit=obj, located=old.located, start=old.located_from, end=obj.located_from)
                located_history.save()

        obj.save()

forms.py

from django import forms
from django.contrib import admin

class EquipmentAdminForm(forms.ModelForm):
    reason = forms.CharField()

    class Meta:
        model = EquipmentAdmin

我想在添加EquipmentLocationHistory时包含reason值，但无法测试我所拥有的内容，因为EquipmentAdminForm不是'已加载。

Answer 1

EquipmentAdmin不是模型。您的 ModelForm 需要引用 Equipment

from django import forms
from django.contrib import admin
from flightdeck.models import Equipment

class EquipmentAdminForm(forms.ModelForm):
    reason = forms.CharField()

    class Meta:
        model = Equipment

PS:当你有循环引用时，有很多方法可以解决这个问题。模型导入和 django 的最佳方法是使用 django.db.models.get_model('app', 'model')