php - 显示我还没有投票的用户 - MySQL

Question

我正在尝试显示我尚未投票的所有用户!

CREATE TABLE IF NOT EXISTS `users` 
(`id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(200) COLLATE utf8_unicode_ci NOT NULL,
`email` varchar(200) COLLATE utf8_unicode_ci NOT NULL,PRIMARY KEY (`id`)
);

CREATE TABLE IF NOT EXISTS `whose_voted` (
`voter_user_id` int(11) NOT NULL,
`voted_on_user_id` int(11) NOT NULL,
PRIMARY KEY (`voter_user_id`,`voted_on_user_id`)
)

CREATE TABLE IF NOT EXISTS `votes` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`yes_count` int(11) NOT NULL,
`beer_count` int(11) NOT NULL,
`total_votes` int(11) NOT NULL,
 PRIMARY KEY (`id`)
)

CREATE TABLE IF NOT EXISTS `user_votes` (
`users_id` int(11) NOT NULL,
`votes_id` int(11) NOT NULL,
 PRIMARY KEY (`users_id`)
)

我有这个查询工作:

/* Show the Names of all users that have not been Voted on */
SELECT users.name
FROM users
 LEFT JOIN user_votes ON users.id = users_id
 LEFT JOIN votes ON votes_id = votes.id
WHERE votes.id IS NULL
ORDER BY users.name

这个查询也有效

/* Show all the User Names that I have voted on */
SELECT users.id AS 'User ID', users.name AS 'I\'ve Voted On'
FROM users
 INNER JOIN whose_voted ON users.id = voted_on_user_id
WHERE whose_voted.voter_user_id = 32 /* my User ID */

我坚持要向用户显示我还没有投票!

** 更新工作查询 ****

/* Show a random users I have Not Voted For as of yet */
SELECT
 unot.id, unot.name
FROM
 users AS unot
WHERE NOT EXISTS (
 /* Exclude the users you have voted on from the total user list */
 SELECT uhave.id
 FROM users AS uhave
  INNER JOIN whose_voted ON uhave.id = voted_on_user_id
 WHERE unot.id = uhave.id 
  AND (whose_voted.voter_user_id = 32)
) 
AND (unot.id != 32)
AND (RAND()<(SELECT ((1/COUNT(*))*10) FROM users))
ORDER BY RAND() 
LIMIT 1;

这个坏男孩一次吐出 1 个随机用户，我还没有投票!感谢您的帮助，非常感谢!

正如您所想象的，我正在对随机出现的人进行投票，这会将他们放入 whose_voted 表中，因此不会再次显示随机查询...任何想要简化我的代码的 SQL 专家？干杯米克

Answer 1

一种方法是将 WHERE NOT EXISTS 与上面的最后一个查询一起用作子查询。当然，未经测试，但应该可以。

SELECT
  users.id AS `User ID`, users.name AS 'I\'ve not Voted On'
FROM
  users unot
WHERE NOT EXISTS (
    /* Exclude the users you have voted on from the total user list */
    SELECT users.id AS
    FROM users uhave
     INNER JOIN whose_voted ON users.id = voted_on_user_id
    WHERE whose_voted.voter_user_id = 32 /* my User ID */
      AND unot.id = uhave.id
)

NOT EXISTS 子查询可能比 JOIN 慢。同样，未经测试。

SELECT
  users.id AS `User ID`, 
  users.name AS 'I\'ve not Voted On'
FROM
  users unot
  LEFT JOIN (
    SELECT users.id AS
    FROM users uhave
     INNER JOIN whose_voted ON users.id = voted_on_user_id
    WHERE whose_voted.voter_user_id = 32 /* my User ID */
  ) uhave ON unot.id = uhave.id
/* NULL in the have voted subquery indicates user hasn't been voted on. */
WHERE uhave.id IS NULL