Python 检查二维列表中是否有空字符串？

Question

我花了几个小时试图解决这个问题，但仍然没有成功。我正在为一项学校作业用 Python 编写 Connect4，我需要一个函数来检查板是否已满。

这是我的init函数

    def __init__( self, width, height ): 
    self.width = width 
    self.height = height 
    self.data = [] # this will be the board 

    for row in range( self.height ): 
        boardRow = [] 
        for col in range( self.width ): 
            boardRow += [' '] 
        self.data += [boardRow] 

我的repr功能

    def __repr__(self): 
    #print out rows & cols 
    s = '' # the string to return 
    for row in range( self.height ): 
        s += '|' # add the spacer character 
        for col in range( self.width ): 
            s += self.data[row][col] + '|' 
        s += '\n' 

s += '--'*self.width + '-\n'

for col in range( self.width ):
    s += ' ' + str(col % 10)
s += '\n'

return s

我的 isFull 函数有什么

    def isFull(self):
# check if board is full
for row in range(0,(self.height-(self.height-1))):
    for col in range(0,self.width):
    if (' ') not in self.data[row][col]:
        return True

我想检查一下数据列表中是否有这个“”(空格)。至少我认为这是我的问题，我没有 python 经验，所以我可能误读了我的问题。如果有人有任何想法，我很乐意倾听。

Answer 1

如果有空间，就表示棋盘未满？

各种版本:

# straightforward but deep
def is_full(self):
    for row in self.data:
        for cell in row:
            if cell == ' ':
                return False
    return True

<小时/>

# combine the last two
def is_full(self):  # python functions/methods are usually lower case
    for row in self.data:  # no need to index everything like c
        if any(cell == ' ' for cell in row):  # any/all are convenient testers
            return False  # if you find even one, it's done.
    return True  # if you couldn't disqualify it, then it looks full

<小时/>

# one line, not especially readable
def is_full(self):
    return not any(cell == ' ' for row in d for cell in row)