python - 用python模拟滚动2个六面骰子的总和

Question

编写 2 个六面骰子滚动的模拟。你的程序应该有一个函数 Roll() 来返回掷骰子的总和。您可以假设六个面中的每一个都有相同的可能性被掷出(即骰子是“公平的”)。运行模拟 1000 次并报告每次总和发生的频率。

到目前为止我已经有了这个，但我的程序似乎不会将总和加起来。我可能完全错了。请提供任何帮助。我认为我的主要问题在于我的打印声明。我需要输出来打印 2 的总和、3 的总和、4 的总和等显示多少次，直到 12。

def Roll():
    for i in range(1000):
        one = 0
        two = 0
        three = 0
        four = 0
        five = 0
        six = 0
        dice1= float(0)
        dice2= float(0)

        dice1 = random.randint(1,6)
        if dice1 == 1:    
            one = one + 1
            count= 1
            return count
        elif dice1 == 2:
            two = two + 1
            count= 1
            return count
        elif dice1 == 3:
            three = three + 1
            count= 1
            return count
        elif dice1 == 4:
            four = four + 1
            count= 1
            return count
        elif dice1 == 5:
            five = five + 1
            count= 1
            return count
        else:
            six = six + 1
            count= 1
            return count

        dice2 = random.randint(1,6)
        if dice2 == 1:    
            one = one + 1
        elif dice2 == 2:
            two = two + 1
        elif dice2 == 3:
            three = three + 1
        elif dice2 == 4:
            four = four + 1
        elif dice2 == 5:
            five = five + 1
        else:
            six = six + 1

        total = one + two + three + four + five + six

        print("2", dice1 + dice2)   
        print("3", dice1 + dice2)
        print("4", dice1 + dice2)
        print("5", dice1 + dice2)
        print("6", dice1 + dice2)    
        print("7", dice1 + dice2)
        print("8", dice1 + dice2)   
        print("9", dice1 + dice2)
        print("10", dice1 + dice2)
        print("11", dice1 + dice2)
        print("12", dice1 + dice2)

Answer 1

我已经用相同的作业回答了你的 friend :

import random
from collections import defaultdict

def main():
    dice = int(input("Enter the number of dice: "))
    sides = int(input("Enter the number of sides: "))
    rolls = int(input("Enter the number of rolls to simulate: "))
    result = roll(dice, sides, rolls)
    maxH = 0
    for i in range(dice, dice * sides + 1):
        if result[i] / rolls > maxH: maxH = result[i] / rolls
    for i in range(dice, dice * sides + 1):
        print('{:2d}{:10d}{:8.2%} {}'.format(i, result[i], result[i] / rolls, '#' * int(result[i] / rolls / maxH * 40)))


def roll(dice, sides, rolls):
    d = defaultdict(int)
    for _ in range(rolls):
        d[sum(random.randint(1, sides) for _ in range(dice))] += 1
    return d

main()

你可以取出对你有用的部分。这还应该涵盖后续问题，例如:“如何整齐地打印它”和“如何绘制直方图”。

<小时/>

示例:

Enter the number of dice: 2
Enter the number of sides: 6
Enter the number of rolls to simulate: 1000
 2        28   2.80% ######
 3        59   5.90% #############
 4        84   8.40% ###################
 5        96   9.60% ######################
 6       155  15.50% ####################################
 7       170  17.00% ########################################
 8       147  14.70% ##################################
 9       102  10.20% #######################
10        80   8.00% ##################
11        50   5.00% ###########
12        29   2.90% ######