Python编码列表 'list'对象没有属性 'encode'

Question

尝试从我试图插入数据库的列表中删除\u0141

results=[['The Squid Legion', '0', u'Banda \u0141ysego', '1', ["\nRazer's Clash of the Gods EU #12 - \nChallonge\n"]], ['Romanian eSports', '1', 'Love', '0', ["\nRazer's Clash of the Gods EU #12 - \nChallonge\n"]]]

results =[[x.encode('ascii', 'ignore')  for x in l] for l in results]

我收到此错误:

AttributeError: 'list' object has no attribute 'encode'

Answer 1

“大列表”中的第一个列表本身包含一个列表 ["\nRazer's Clash of the Gods EU #12 -\nChallonge\n"]，它显然没有 encode() 方法。

那么你的算法中发生的事情是这样的:

[[somestring.encode, somestring.encode, somestring.encode, [somestring].encode, ...]

不过，您可以使用简单的递归算法:

def recursive_ascii_encode(lst):
    ret = []
    for x in lst:
        if isinstance(x, basestring):  # covers both str and unicode
            ret.append(x.encode('ascii', 'ignore'))
        else:
            ret.append(recursive_ascii_encode(x))
    return ret

print recursive_ascii_encode(results)

输出:

[['The Squid Legion', '0', 'Banda ysego', '1', ["\nRazer's Clash of the Gods EU #12 - \nChallonge\n"]], ['Romanian eSports', '1', 'Love', '0', ["\nRazer's Clash of the Gods EU #12 - \nChallonge\n"]]]

当然，这实际上是更通用的递归映射的特例，重构后如下所示:

def recursive_map(lst, fn):
    return [recursive_map(x, fn) if isinstance(x, list) else fn(x) for x in lst]

print recursive_map(results, lambda x: x.encode('ascii', 'ignore'))