python - 涉及列表的格式问题

Question

我有这个函数，它将名称作为输入，将其放入列表中，然后对其运行 ord() 。但是，我遇到了一些(我认为的)格式问题。我试图让它看起来像这样:

b = (ascii value)
a = (ascii value)
t = (ascii value)
m = (ascii value)
a = (ascii value)
n = (ascii value)

我的名称显示正确，但 ascii 值显示如下:

b = [98, 97, 116, 109, 97, 110]
a = [98, 97, 116, 109, 97, 110]
t = [98, 97, 116, 109, 97, 110]
m = [98, 97, 116, 109, 97, 110]
a = [98, 97, 116, 109, 97, 110]
n = [98, 97, 116, 109, 97, 110]

不确定我哪里出错了，下面是我为此编写的代码:

def x():
     name = requestString("name")
     usersName = list(name)
     ascii = [orc(c) for c in usersName]
     for name in name: 
          print name, "=", ascii 

谢谢!

编辑:谢谢，真的很感激。现在就找出我错在哪里!

Answer 1

以下是对您出错的地方的一些回顾:

def x():
     name = requestString("name")
     usersName = list(name)
     ascii = [orc(c) for c in usersName] # here's the list
     for name in name: 
          print name, "=", ascii # and you're printing it here everytime

你可以像这样更Python地修复:

def x():
     name = requestString("name")
     # usersName = list(name) # no need for this line, you can iterate over the string
     ascii = [orc(c) for c in name] #so this is just name
     for i, c in enumerate(name):  # use c for your character var name, 
          print c, "=", ascii[i]   # and enumerate provides the index

由于您没有返回任何内容，因此没有必要创建列表，您不妨即时提供 ord(c):

def print_ords_of_word(name):
    for c in name:
        print c, '=', ord(c)