python - 将嵌套列表转换为嵌套元组

Question

请问我如何循环遍历嵌套列表以从中获取元组的嵌套列表，例如循环遍历 pot 以获得 rslt

pot = [[1,2,3,4],[5,6,7,8]]

我试过了

b = []

for i in pot:
    for items in i:
        b = zip(pot[0][0:],pot[0][1:])

但没有得到所需的输出谢谢

期望的结果=

rslt = [[(1,2),(3,4)],[(5,6),(7,8)]]

Answer 1

基于石斑鱼 recipe in the itertools documentation ，您可以尝试这样的操作(假设您的子列表是您指定的长度):

>>> def grouper(iterable, n):
    args = [iter(iterable)] * n  # creates a list of n references to the same iterator object (which is exhausted after one iteration)
    return zip(*args)

现在您可以测试一下:

>>> pot = [[1,2,3,4],[5,6,7,8]]
>>> rslt = []
>>> for sublist in pot:
    rslt.append(grouper(sublist, 2))
>>> rslt
[[(1, 2), (3, 4)], [(5, 6), (7, 8)]]