python - 基于 bool 值的 Django 管理下拉菜单

Question

我想知道如何根据 bool 值过滤下拉列表。假设其中一个对象是 True，那么它将被显示，但如果它是 False，那么它就不会被显示。

任何帮助都会很棒。这是我的模型和管理文件的副本

模型.py

class Airports(models.Model):
    id = models.AutoField("ID", primary_key=True, editable=False,)
    airporticao = models.CharField("Airport ICAO", max_length=6, help_text="Example: CYYZ or KLGA")
    airportname = models.CharField("Airport name", max_length=50, help_text="Example:")
    country = models.CharField("Country", max_length=50, help_text="Example: Canada")
    hub = models.BooleanField("Hub?", default=False)

admin.py 用于配置文件模块:

class UserProfileadmin(admin.ModelAdmin):
    list_display = ['user', 'country', 'vatsimid', 'totalflights', 'totalhours', 'hub']
    search_fields = ['user']

Answer 1

哦。试试这个:

class UserProfileadmin(admin.ModelAdmin):
    def formfield_for_foreignkey(self, db_field, request, **kwargs):
        if db_field.name == 'hub':
            kwargs['queryset'] = Airports.objects.filter(hub=True)
        return super(UserProfileadmin, self).formfield_for_foreignkey(db_field, request, **kwargs)

有关 formfield_for_foreignkey 的文档.