c# - AutoMapper - 将 2 个对象列表合并为 1 个列表

Question

我看过一些示例，您可以在其中使用 AutoMapper 将来自多个来源的数据组合到一个来源。

我的问题是，当我处理数据列表时，我如何才能做到这一点？

编辑:在我的示例中，List(Person) 将映射到 List(PersonCompany)，但是 List(Company) 到 List(PersonCompany) 的映射不映射。

编辑 2:更改映射器以更新模型，但是公司映射现在是唯一被映射的数据。

假设我有以下类(class):

public class Person
{
    public int ID { get; set; }
    public string Name { get; set; }
    public string PhNo { get; set; }
}
public class Company
{
    public int PersonID { get; set; }
    public int EmpNo { get; set; }
    public string Title { get; set; }
}

public class PersonCompany
{
    public string Name { get; set; }
    public string PhNo { get; set; }

    public int EmpNo { get; set; }
    public string Title { get; set; }

    public int ID { get; set; }
}

现在这个简单的例子可以工作了......

    // This is a simple example using AutoMapper to map 2 source objects into one destination object.
    var personMapConfig = new MapperConfiguration(c =>
        c.CreateMap<Person, PersonCompany>()
        .ForMember(x => x.Name, y => y.MapFrom(a => a.Name))
        .ForMember(x => x.PhNo, y => y.MapFrom(a => a.PhNo))
        .ForMember(x => x.ID, y => y.MapFrom(a => a.ID))
        );

    var companyMapConfig = new MapperConfiguration(c =>
    c.CreateMap<Company, PersonCompany>()
    .ForMember(d => d.EmpNo, opt => opt.MapFrom(s => s.EmpNo))
    .ForMember(d => d.Title, opt => opt.MapFrom(s => s.Title))
    );

    var person = new Person { ID=1, Name = "PersonName", PhNo = "212-000-0000" };            
    var company = new Company { PersonID = 1, Title = "Associate Director", EmpNo = 10001 };


    var model = personMapConfig.CreateMapper().Map<Person, PersonCompany>(person);
    companyMapConfig.CreateMapper().Map<Company, PersonCompany>(company, model);

但是，当我处理数据列表时，它不会。

    var personList = new List<Person> { new Person { ID=1, Name="David Johnson", PhNo="(111) 111-1111"},
                                        new Person { ID=2, Name="Marvin Miller", PhNo="(222) 222-2222"},
                                        new Person { ID=3, Name="Jack Wilson", PhNo="(333) 333-3333"}};

    var companyList = new List<Company> { new Company { EmpNo= 1, PersonID = 1, Title="Director"},
                                        new Company { EmpNo= 2, PersonID = 2, Title="Surgeon"},
                                        new Company { EmpNo= 3, PersonID = 3, Title="Sales"}};

    var personMapConfig = new MapperConfiguration(c =>
        c.CreateMap<Person, PersonCompany>()
        .ForMember(x => x.Name, y => y.MapFrom(a => a.Name))
        .ForMember(x => x.PhNo, y => y.MapFrom(a => a.PhNo))
        .ForMember(x => x.ID, y => y.MapFrom(a => a.ID))
    );

    var companyMapConfig = new MapperConfiguration(c =>
        c.CreateMap<Company, PersonCompany>()
        .ForMember(d => d.EmpNo, opt => opt.MapFrom(s => s.EmpNo))
        .ForMember(d => d.Title, opt => opt.MapFrom(s => s.Title))
    );

    var model = personMapConfig.CreateMapper().Map<List<Person>, List<PersonCompany>>(personList);
    companyMapConfig.CreateMapper().Map<List<Company>, List<PersonCompany>>(companyList, model);

Answer 1

最后两行调用 .Map<List<Person>, List<PersonCompany>()和 .Map<List<Company>, List<PersonCompany>>() .这两个调用都会返回您期望的值。问题是您没有加入数据。您只告诉它如何转换 Person -> PersonCompany和 Company -> PersonCompany ，而不是如何将数据连接在一起。

我怀疑您是否需要为此使用 AutoMapper。以下作品:

var personList = new List<Person> { new Person { ID=1, Name="David Johnson", PhNo="(111) 111-1111"},
                                        new Person { ID=2, Name="Marvin Miller", PhNo="(222) 222-2222"},
                                        new Person { ID=3, Name="Jack Wilson", PhNo="(333) 333-3333"}};

var companyList = new List<Company> { new Company { EmpNo= 1, PersonID = 1, Title="Director"},
                                    new Company { EmpNo= 2, PersonID = 2, Title="Surgeon"},
                                    new Company { EmpNo= 3, PersonID = 3, Title="Sales"}};

var personCompanies = companyList.Join(personList, m => m.PersonID, m => m.ID, (c, p) => new PersonCompany {
    Name = p.Name,
    PhNo = p.PhNo,
    EmpNo = c.EmpNo,
    ID = p.ID,
    Title = c.Title
});