c# - 异步 MVC Controller 和 HttpTaskAsyncHandler

Question

我正在尝试为我的自定义内容管理解决方案实现自定义 HttpTaskAsyncHandler。这个想法是将 /100/my-little-pony 路由到 /Details/my-little-pony。我希望通过以下 HttpTaskAsyncHandler 实现此目的:

public override async Task ProcessRequestAsync(HttpContext context)
{
    try
    {
        var id = GetContentIdFromRouteData();

        // Retrieve the content identified by the specified ID
        var contentRepository = new ContentRepository();
        var content = await contentRepository.GetAsync(id);

        if (content == null)
            throw new ContentNotFoundException(id);

        // Initialize an instance of the content controller
        var factory = ControllerBuilder.Current.GetControllerFactory();
        var controller = (IContentController) factory.CreateController(_requestContext, content.ControllerName);
        if (controller == null)
            throw new ControllerNotFoundException(content.ControllerName);

        try
        {
            // Retrieve all content type values and pass them on the the method for index pages
            var action = _requestContext.RouteData.GetRequiredString("action");
            if (action == "Index")
            {
                ContentType data = null;
                if (controller.ContentType != null)
                {
                    data = BusinessHost.Resolve<ContentType>(controller.ContentType);
                    data.Values = content.Parameters.ToDictionary(p => p.Name, p => p.Value);
                }
                _requestContext.RouteData.Values.Add("data", data);
            }

            var values = _requestContext.RouteData.Values;
            values.Add("name", content.Name);
            values.Add("controllerId", id);
            values.Add("controller", content.ControllerName);

            controller.Execute(_requestContext);
        }
        finally
        {
            factory.ReleaseController(controller);
        }
    }
    catch (ContentNotFoundException ex)
    {
        Trace.TraceWarning($"404: {ex.Message}");
        _requestContext.HttpContext.Response.StatusCode = (int)HttpStatusCode.NotFound;
    }
}

这对于同步请求非常有效，但是当我尝试调用异步方法时......

@using (Html.BeginForm("Save", Html.ControllerId(), FormMethod.Post, new { @class = "form-horizontal" }))

...这就是方法...

[HttpPost]
public async Task<ActionResult> Save(NewsViewModel model)
{ }

编辑 我已将方法名称更改为保存，因为未推断异步，我收到一个新错误:

The asynchronous action method 'Login' returns a Task, which cannot be executed synchronously.

Answer 1

操作名称是 SaveAsync，但引用它的代码使用 Save 作为名称。任何操作都没有神奇的重命名，包括异步一次。

您的选择:

• 使用 SaveAsync 来引用操作
• 使用ActionName attribute重命名 Action
• 将方法重命名为Save(但这违反了所有async 方法都具有...Async 后缀的约定)

旁注:与某些自定义处理程序相比，使用路由可能是重定向的更好选择。