c# - 使用 Flurl GetResponseJson() 的单元测试代码

Question

我正在尝试对捕获 FlurlHttpException 的 Controller 进行单元测试并调用 GetResponseJson<TError>()在 catch block 中获取错误消息。我试图模拟异常，但是 Call属性不允许我设置 Settings .单元测试运行时失败，因为设置中没有 JsonSerializer。如何设置此测试？

这是我目前的尝试，但没有成功:

Controller

[Route]
public async Task<IHttpActionResult> Post(SomeModel model)
{
    try
    {
        var id = await _serviceClient.Create(model);

        return Ok(new { id });
    }
    catch (FlurlHttpException ex)
    {
        if (ex.Call.HttpStatus == HttpStatusCode.BadRequest)
           return BadRequest(ex.GetResponseJson<BadRequestError>().Message);
        throw;
    }
}

单元测试

[TestMethod]
public async Task Post_ServiceClientBadRequest_ShouldReturnBadRequestWithMessage()
{
    //Arrange
    string errorMessage = "A bad request";
    string jsonErrorResponse = JsonConvert.SerializeObject(new BadRequestError { Message = errorMessage });
    var badRequestCall = new HttpCall
    {
        Response = new HttpResponseMessage(HttpStatusCode.BadRequest),
        ErrorResponseBody = jsonErrorResponse
        //This would work, but Settings has a private set, so I can't
        //,Settings = new FlurlHttpSettings { JsonSerializer = new NewtonsoftJsonSerializer(new JsonSerializerSettings()) }
    };

    _mockServiceClient
        .Setup(client => client.create(It.IsAny<SomeModel>()))
        .ThrowsAsync(new FlurlHttpException(badRequestCall, "exception", new Exception()));

    //Act
    var result = await _controller.Post(new SomeModel());
    var response = result as BadRequestErrorMessageResult;

    //Assert
    Assert.IsNotNull(response);
    Assert.AreEqual(errorMessage, response.Message);
}

Answer 1

如果你在你的ServiceClient对象中封装了Flurl的用法，那么我认为捕获FlurlException，提取Message，并返回一个更合适的异常也应该封装在那个服务中。这将使您的 Controller 更容易测试。