python - 如何根据空间而不是换行进行分割？

Question

我有以下代码，它删除了“refs/changes/digit”，但没有得到预期的输出，我的当前输出如下所示，任何人都可以提供输入如何解决这个问题？

source="refs/changes/44/1025744/3 refs/changes/62/1025962/5 refs/changes/45/913745/2"
output = ' '.join(line.split('/', 3)[-1] for line in source.splitlines())
print output


CURRENT OUTPUT:-

1025744/3 refs/changes/62/1025962/5 refs/changes/45/913745/2

expected output

1025744/3 1025962/5 913745/2

Answer 1

按空格拆分，然后按前三个 "/" 拆分并提取最后一个元素。

source="refs/changes/44/1025744/3 refs/changes/62/1025962/5 refs/changes/45/913745/2"
print(" ".join([ele.split("/",3)[-1] for ele in source.split()]))
1025744/3 1025962/5 913745/2

一些时间安排:

In [3]: import re

In [4]: timeit " ".join([ele.split("/",3)[-1] for ele in source.split()])
100000 loops, best of 3: 1.83 µs per loop

In [5]: timeit p.findall(source)

100000 loops, best of 3: 2.84 µs per loop