c# - 旋转曲线(一系列数据点)X 度定义了它们的新基线

Question

我正在使用 MSchart 将 serie 绘制到其中，我需要将曲线(数据点系列)旋转 X 度，P1 是第一次点击(mouseDown)，P2 是第二次点击(mouseUp)，P1 和 P2 之间的角度代表角度旋转(我有这个计算)，问题是当我应用不同的方法来做这个时曲线变形

for (int x = 1; x < curve.nPoints; x++)
{   
     double X0 = curve.get_array_X[x];
     double Y0 = curve.get_array_Y[x];

     System.Windows.Media.Matrix m = new System.Windows.Media.Matrix();
     m.Rotate(45 * (Math.PI / 180.0));
     System.Windows.Vector v = new System.Windows.Vector(X0, Y0);
     v = System.Windows.Vector.Multiply(v, m);
     sAus.Points.AddXY(v.X, v.Y);
}

和其他代码

public Series nueva(float X, float Y)
    {
        Series sAus = new Series(curvaActual.Tag);
        int nearest1 = curvaActual.FindNearestXCV(new DataPoint(chartWorking1.ChartAreas[0].AxisX.PixelPositionToValue(X),
                                 chartWorking1.ChartAreas[0].AxisY.PixelPositionToValue(Y)).XValue,
                                 new DataPoint(chartWorking1.ChartAreas[0].AxisX.PixelPositionToValue(X), chartWorking1.ChartAreas[0].AxisY.PixelPositionToValue(Y)).YValues[0], 0, curvaActual.nPoints);
        int nearest2 = curvaActual.FindNearestXCV(new DataPoint(chartWorking1.ChartAreas[0].AxisX.PixelPositionToValue(X),
                                      chartWorking1.ChartAreas[0].AxisY.PixelPositionToValue(Y)).XValue,
                                      new DataPoint(chartWorking1.ChartAreas[0].AxisX.PixelPositionToValue(X), chartWorking1.ChartAreas[0].AxisY.PixelPositionToValue(Y)).YValues[0], 0, curvaActual.nPoints);

        double x1 = (double)curvaActual.get_array_X[nearest1];
        double y1 = (double)curvaActual.get_array_Y[nearest1];


        double x2 = (double)curvaActual.get_array_X[nearest2];
        double y2 = (double)curvaActual.get_array_Y[nearest2];
        double pendiente = Math.Atan2(y2 - y1, x2 - x1);
        double anguloF = pendiente;
        double deg = Math.PI * 45 / 180.0;
        double coseno = Math.Cos(deg);
        double seno = Math.Sin(deg);

        double[] arrayX = new double[curvaActual.nPoints];
        double[] arrayY = new double[curvaActual.nPoints];

        for (int x = 1; x < curvaActual.nPoints; x++)
        {

            PointF rotatedPoint = RotatePoint(new PointF((float)curvaActual.get_array_X[x], (float)curvaActual.get_array_Y[x]), new PointF((float)curvaActual.get_array_X[x - 1], (float)curvaActual.get_array_Y[x - 1]), 45);
            double angleRotatedPoint = angleFromPoint(rotatedPoint, new PointF((float)curvaActual.get_array_X[x - 1], (float)curvaActual.get_array_Y[x - 1]));


            PointF pointROtado = RotatePoint(new PointF((float)curvaActual.get_array_X[x], (float)curvaActual.get_array_Y[x]), new PointF((float)0, (float)0), 45);
            sAus.Points.AddXY((double)pointROtado.X, (double)pointROtado.Y);

        }

        return sAus;
    }

[证明]

原创系列

旋转33

使用你的代码(将point修改为pointF)

void rotateSeries(Series src, Series tgt, DataPoint center, float angle)
    {

        PointF c = new PointF((float)center.XValue, (float)center.YValues[0]);

        tgt.Points.Clear();
        foreach (DataPoint dp in src.Points)
        {
            PointF p0 = new PointF((float)dp.XValue, (float)dp.YValues[0]);
            PointF p = RotatePoint(p0, c, angle);
            tgt.Points.AddXY(p.X, p.Y);
        }
    }
    static PointF RotatePoint(PointF pointToRotate, PointF centerPoint, double angleInDegrees)
    {
        double angleInRadians = angleInDegrees * (Math.PI / 180);
        double cosTheta = Math.Cos(angleInRadians);
        double sinTheta = Math.Sin(angleInRadians);
        return new PointF
        {
            X = (float)
                (cosTheta * (pointToRotate.X - centerPoint.X) -
                sinTheta * (pointToRotate.Y - centerPoint.Y) + centerPoint.X),
            Y = (float)
                (sinTheta * (pointToRotate.X - centerPoint.X) +
                cosTheta * (pointToRotate.Y - centerPoint.Y) + centerPoint.Y)
        };
    }

Answer 1

这是您如何做到这一点的一个示例。它..

• 假设您已找到要围绕其旋转图形的 DataPoint 中心
• 假设您已经计算出它应旋转的角度
• 使用两个 Series s1 和 s2，第一个是源，后者是旋转的目标。
• 使用 RotatePoint 的版本来自 Fraser 的 anwser，针对 PointF 稍作更新。

这是围绕第 5 个点旋转 33 度的结果:

private void button1_Click(object sender, EventArgs e)
{
    rotateSeries(s1, s2, s1.Points[4], 33);
}

void rotateSeries(Series src, Series tgt, DataPoint center, float angle)
{

    PointF c = new PointF((float)center.XValue, (float)center.YValues[0]);

    tgt.Points.Clear();
    foreach (DataPoint dp in src.Points)
    {
        PointF p0 = new Point((float)dp.XValue, (float)dp.YValues[0]);
        PointF p = RotatePoint(p0, c, angle);
        tgt.Points.AddXY(p.X, p.Y);
    }
}

static PointF RotatePoint(PointF pointToRotate, PointF centerPoint, double angleInDegrees)
{
    double angleInRadians = angleInDegrees * (Math.PI / 180);
    double cosTheta = Math.Cos(angleInRadians);
    double sinTheta = Math.Sin(angleInRadians);
    return new PointF
    {
        X = (float)
            (cosTheta * (pointToRotate.X - centerPoint.X) -
            sinTheta * (pointToRotate.Y - centerPoint.Y) + centerPoint.X),
        Y = (float)
            (sinTheta * (pointToRotate.X - centerPoint.X) +
            cosTheta * (pointToRotate.Y - centerPoint.Y) + centerPoint.Y)
    };
}

如果您想使用 MouseClick 来确定角度，您可以直接使用 e 参数中的 Points。但要找出中心，您需要将像素坐标转换为图表值坐标。

这是您可以在 MouseClick 事件期间使用的调用:

DataPoint clickedValuePoint(ChartArea ca, Point pt)
{
    return new DataPoint(ca.AxisX.PixelPositionToValue(pt.X), 
                         ca.AxisY.PixelPositionToValue(pt.Y));
}

现在让我们看看它是如何工作的，使用 DataPoint:

DataPoint centerPoint = null;

private void chart1_MouseClick(object sender, MouseEventArgs e)
{
    ChartArea ca = chart1.ChartAreas[0];
    centerPoint = clickedValuePoint(ca, e.Location);

    rotateSeries(s1, s2, centerPoint, 33);
}