c# - pjsip c#, System.AccessViolationException 在一个单独的线程上接听来电

Question

在 overrided void onIncomingCall 中，我打开了一个新的后台线程，它显示了一个 new (Popup) Form。我尝试接听或拒绝此表单中的调用，但随后收到 System.AccessViolationException。似乎当前的调用对象被锁定，无法从另一个窗体访问。如果我在 onIncomingCall void 中使用 currentcall.answer(prm)，则调用已成功建立(没有其他表单和线程)。

public class myaccount : Account
{

   public override void onIncomingCall(OnIncomingCallParam prm)
   {
       Call call = new Call(this, prm.callId);
       CallOpParam param = new CallOpParam();


       param.statusCode = pjsip_status_code.PJSIP_SC_RINGING;
       param.statusCode = pjsip_status_code.PJSIP_SC_OK;
       pjsipfunctions.currentparam = param;
       pjsipfunctions.currentcall = call;


       var thread = new Thread(() =>
       {
           ShowPopup(call,prm.callId.ToString());

       });
       thread.SetApartmentState(ApartmentState.STA);
       thread.Start();

       //    Thread myCallingThread = new Thread(new ThreadStart(ShowPopup));
       //myCallingThread.SetApartmentState(ApartmentState.STA);
       //myCallingThread.IsBackground = true;
       //myCallingThread.Start();



   }
   public void ShowPopup(Call myCall,string call_id)
   {
       IncommingCallPopup win = new IncommingCallPopup(ref myCall, call_id );

       win.Show();
       System.Windows.Threading.Dispatcher.Run();


     }


}

#####################################
public IncommingCallPopup(ref  Call info, string callid)
   {
       currentCall = info;
        Callid = callid;
       CurrentCall = currentCall;
       Prm.statusCode = pjsip_status_code.PJSIP_SC_RINGING;
       InitializeComponent();
       labelCallId.Content = callid;

   }

   private void rejectcall(object sender, RoutedEventArgs e)
   {
       Prm.statusCode = pjsip_status_code.PJSIP_SC_DECLINE;
       CurrentCall.hangup(Prm);
   }

   private void transfercall(object sender, RoutedEventArgs e)
   {

   }

   private void takecall(object sender, RoutedEventArgs e)
   {

       Prm.statusCode = pjsip_status_code.PJSIP_SC_OK;
       try
       {
           CurrentCall.answer(Prm);
       }
       catch(Exception ex)
       {

       }

   }

Answer 1

经过疯狂的搜索和尝试，我已经弄明白了。每个线程都必须在端点中注册，您可以在另一个类(窗口)中挂断、接听或转移调用。

您只需在公共(public)类中编写此方法，并在每次从另一个窗口调用您的 void 时调用此 void ->

public void callpopup(String number) {
     checkThread();

//answer, decline or something else

}

[MethodImpl(MethodImplOptions.Synchronized)]
    public static void checkThread()
    {
        try
        {

            if (ep != null && !ep.libIsThreadRegistered())
                ep.libRegisterThread(Thread.CurrentThread.Name);

        }
        catch (Exception e)
        {


        }
    }