python - 从Python中的列表创建字典

Question

我有一个路径列表，例如['aaa/aaa.csv', 'aaa/bbb.csv', 'aaa/ccc.csv']。如何将其转换为字典，如 {'aaa':['aaa.csv', 'bbb.csv', 'ccc.csv'] 等，路径中的第一个文件夹等于其他的？

我尝试了这段代码，但很困惑下一步该做什么。

list_split = [i.split('/') for i in list]

dic = {}
list_temp = []
for item in list_split:
    list_temp.append(item)
    if len(list_temp) < 2:
        pass
    else:
        for itemm in list_temp:
            pass

Answer 1

dic = {}
lst = ['aaa/aaa.csv', 'aaa/bbb.csv', 'aaa/ccc.csv']
for item in lst:
    slash = item.find('/')
    key = item[:slash]
    val = item[slash+1:]
    if dic.has_key(key):
        dic[key].append(val)
    else:
        dic[key] = [val]

>>> dic
{'aaa': ['aaa.csv', 'bbb.csv', 'ccc.csv']}