python - 值错误: Expecting value: line 1 column 1 (char 0)

Question

检查了类似问题的其他答案，但找不到解决此特定问题的任何内容。我不明白为什么会出现错误，因为我不相信我丢失了任何值。另外，我认为它说的是第 1 行第 1 列(字符 0)，这很奇怪 - 你们这些优秀的人有什么想法吗？

import json
import urllib.request

user_agent = "Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.9.0.7) Gecko/2009021910 Firefox/3.0.7"

url = "http://api.usatoday.com/open/articles/topnews?encoding=json&api_key=98jv5a93qs"

headers={"User-Agent":user_agent,} 

request = urllib.request.Request(url, None, headers)

parsed_json = json.loads(str(request))

for i in range(6):
    title = parsed_json['stories'][i]['title']
    link = parsed_json['stories'][i]['link']
    print(title)
    print(link)
    print("-----------------------------------")

Answer 1

您正在尝试解析响应 JSON。但您没有发送请求。您应该发送您的 Request，然后解析响应 JSON:

import json
import urllib.request

user_agent = "Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.9.0.7) Gecko/2009021910 Firefox/3.0.7"

url = "http://api.usatoday.com/open/articles/topnews?encoding=json&api_key=98jv5a93qs"

headers={"User-Agent":user_agent,}

request = urllib.request.Request(url, None, headers)
res = urllib.request.urlopen(request)

parsed_json = json.loads(res.readall())

for i in range(6):
    title = parsed_json['stories'][i]['title']
    link = parsed_json['stories'][i]['link']
    print(title)
    print(link)
    print("-----------------------------------")