php - Codeigniter 事件记录类(从哪里选择)

Question

只是想让 codeigniter 过滤器表单工作。例如，如果将从下拉列表中选择“Samsung”并从复选框字段中选择“2G”，则应返回 ID 为 1 和 4 的行。但是我的模型返回空数组。请帮助我。

这是我的数据库表:

这是我的过滤器形式:

这是我的模型:

 <?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');

    class Model_example extends CI_Model {

      function __construct()
     { 
       parent::__construct();
     }

    public function did_filter() {


   $types = $this->input->post('types');

        $data = array(
            '2g' => 0,
                '3g' => 0,
                '4g' => 0,                
                     );                  
        foreach ($types as $type) {
                                       $data[$type] == 1;
                                  }
$this->db->select('*');
$this->db->from('table_example');
$this->db->where('phone', $this->input->post('phone'));
$this->db->where((
    (('2g' == 1) AND ($data['2g'] == 1)) OR
    (('3g' == 1) AND ($data['3g'] == 1)) OR  
    (('4g' == 1) AND ($data['4g'] == 1))
    ),NULL, FALSE );
       if (
       $query = $this->db->get())
       {            
    return $result = $query->row_array();
        }
        else {
        return false;
        }
        }  
    }

这是我的观点 1:

    <?php 

             $this->load->helper("form","file");

             echo validation_errors();              

             echo form_open_multipart("example/search");

             echo form_label("Phone:<br>","phone");
             $data = array(
                  "" => "Select Phone",
                  "samsung" => "Samsung",
                  "htc" => "HTC",
                  "nokia" => "Nokia",
                );
             echo form_dropdown('phone', $data, set_value('phone'));

             echo br(5);
              ?> 

             <?php echo form_label("Network Type:<br>","type");?>                   
<input type="checkbox" name="types[]" value="2g" id="types"  <?php echo set_checkbox('types[]', '2g', FALSE); ?>/>2G<br />
<input type="checkbox" name="types[]" value="3g" id="types" <?php echo set_checkbox('types[]', '3g', FALSE); ?>/>3G<br />
<input type="checkbox" name="types[]" value="4g" id="types" <?php echo set_checkbox('types[]', '4g', FALSE); ?>/>4G<br />
<br />          
             <?php

             echo br(1);

             echo form_submit("filterSearch", "Search");

             echo form_close();

             ?>

这是我的观点 2:

<?php 

       print_r($result);     

这是我的 Controller :

<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');

class Example extends MX_Controller {

    public function index() { //main function

        $this->load->view("view_example");
    }

public function search() { 

            $this->load->library('form_validation');
            $this->load->model('model_example');

            $this->form_validation->set_rules('phone', 'Phone','required');
            $this->form_validation->set_rules('types[]', 'Network Type','required'); 

           if($this->form_validation->run()) {

            $data["result"] = $this->model_example->did_filter();


            $this->load->view("view_search_results",$data); 

            }
            else
            {

            $this->load->view("view_no_search_results");

             }

    }
}

Answer 1

public function did_filter($phone, $2g, $3g, $4g){

   //setup query
   $this->db->select('id, phone, 2g, 3g, 4g')
       ->from('example_table')
       ->where('phone', $phone)
       ->where('2g', $2g)
       ->where('3g', $3g)
       ->where('4g', $4g);

    //execute query
    $query = $this->db->get();

    //fetch result
    return $result = $query->row_array();
}

这将返回一个结果数组。

解决使用问题

echo $this->db->last_query;

然后在 phpMyAdmin 中运行生成的字符串以帮助调试。

同时修复您的 HTML 输入。

<input type="checkbox" name="2g" value="1" id="types" />2G<br />
<input type="checkbox" name="3g" value="1" id="types" />3G<br />
<input type="checkbox" name="4g" value="1" id="types" />4G<br />