Python:按键、值比较两个相同的字典

Question

我想比较两个字典的长度以及每个字典中每个键、值对的长度。如果在查找时没有匹配项，我还需要能够打印出来。

我当前的代码似乎传递了长度标准，但在尝试匹配元素时失败:

assert_that(len(model_dict), len(server_dict))
    for x in model_dict:
        if x not in server_dict and model_dict[x] != server_dict[x]:
            print(x, model_dict[x])

server_dict 字典中一个条目的示例:

{2847001: [[[-94.8, 28], [-95.4, 28], [-96, 28], [-96.5, 28.1], [-96.667, 28.133], [-97, 28.2], [-97.6, 28.3], [-98.3, 28.4], [-98.9, 28.6], [-99.4, 29], [-99.8, 29.5], [-100, 30], [-100.1, 30.5], [-100.2, 31]]]}

model_dict 字典中一个条目的示例:

{2847001: [[-94.8, 28], [-95.4, 28], [-96, 28], [-96.5, 28.1], [-96.667, 28.133], [-97, 28.2], [-97.6, 28.3], [-98.3, 28.4], [-98.9, 28.6], [-99.4, 29], [-99.8, 29.5], [-100, 30], [-100.1, 30.5], [-100.2, 31]]}

Answer 1

错误似乎是在条件中使用and:

x not in server_dict and model_dict[x] != server_dict[x]

如果第一个条件成立，第二个条件就没有意义了。尝试使用 或 代替:

x not in server_dict or model_dict[x] != server_dict[x]