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mysql - 添加到 MySQL 查询

转载 作者:行者123 更新时间:2023-11-30 23:03:43 26 4
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当在表单中选择性别时,我想在我的查询中添加一个 WHERE。

我正在使用 bindParam 来使用一个下拉菜单来获取年份,但我想要第二个 bindParam,它向查询插入一个“AND Gender =”,并用一个“$_GET['dropdowngender'] 来填充它。

我想使用 if 语句来查看是否正在使用下拉菜单,以及是否正在选择性别以将信息添加到查询中。

<?php

@include ('conn.php');

$query = $db->prepare("SELECT Name, MAX(Count) AS MaxCount, ZIPcode, Year FROM Name_Data WHERE Year = :year AND Name_Data.Count = ( SELECT MAX( Count ) FROM Name_Data AS f WHERE f.id = Name_Data.id ) GROUP BY ZIPcode");

$query->bindParam(':jaar', $_GET['dropdownyear'], PDO::PARAM_STR, 30);

$query->execute();

$result = $query->fetchAll (PDO::FETCH_ASSOC);

$jsonResult = json_encode($result);

echo $jsonResult;

?>

这是我的首页

<form method="post" action="#" id="form">
<select name="dropdownyear" id="menuyear">
<option selected>Choose a year</option>
</select>
<select name="dropdowngender" id="menugender">
<option value="M">Male</option>
<option value="F">Female</option>
</select>
</form>

我的 jquery 脚本

$( "#form" )
.change(function(){
$(".marker").empty();
var SelectYear= $("#menuyear option:selected").text();

$.getJSON( "sql.php", { dropdownjaar: SelectYear }, function(jsonData) {
console.log( jsonData );

$.each( jsonData, function(key,row) {
var newDiv=$('<div>');
var Content = row ['Name'] + ' ';
newDiv.text(Content);
}); // each

}); //get json
}); // change function

最佳答案

这可能对您有帮助:

$query = "SELECT Name, MAX(Count) AS MaxCount, ZIPcode, Year 
FROM Name_Data
WHERE Year = :year ";
if( isset( $_GET['dropdowngender'] ) {
$query = $query . " AND gender = :gender ";
}

$query = $query . " AND Name_Data.Count =
( SELECT MAX( Count ) FROM Name_Data AS f
WHERE f.id = Name_Data.id
) GROUP BY ZIPcode";

$query->bindParam(':year', $_GET['dropdownyear'], PDO::PARAM_STR);
if( isset( $_GET['dropdowngender'] ) {
$query->bindParam(':gender', $_GET['dropdowngender'], PDO::PARAM_STR);
}

关于mysql - 添加到 MySQL 查询,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22768468/

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