python - SparkPost:至少需要一个有效的收件人 python/django API

Question

我在使用 SparkPost 发送电子邮件时遇到问题:我的代码如下:

from configurations.global_configs import site_base_url
from media.settings import SPARKPOST_API_KEY
from sparkpost import SparkPost
import traceback

def welcome_email(user_profile):
    try:
        user_profile.confirmation_key = user_profile.generate_key()
        user_profile.save()
        email_address = user_profile.user.email
        print email_address
        name = user_profile.user.first_name or email_address
        email_confirmation_url = site_base_url + "api/account/signup/?ck=" + user_profile.confirmation_key
        print email_confirmation_url
        sp = SparkPost(SPARKPOST_API_KEY)
        result = sp.transmissions.send(
            recipients=[email_address],
            template='welcome',
            subject='this is my subject',
            track_opens=True,
            track_clicks=True,
            substitution_data={
                'email_validation_url': email_confirmation_url
            },
            transactional= True
        )
        return result
    except:
        traceback.print_exc()

但是我的代码输出如下并返回此错误:

exampleemail@gmail.com
http://example.com/api/account/signup/?ck=1144f138439dc42e
Traceback (most recent call last):
  File "./users_system/services/email_confirm.py", line 28, in welcome_email
    transactional= True
  File "/usr/local/lib/python2.7/dist-packages/sparkpost/transmissions.py", line 142, in send
    results = self.request('POST', self.uri, data=json.dumps(payload))
  File "/usr/local/lib/python2.7/dist-packages/sparkpost/base.py", line 26, in request
    raise SparkPostAPIException(response)
SparkPostAPIException: Call to https://api.sparkpost.com/api/v1/transmissions returned 400, errors:

        At least one valid recipient is required:

如您所见，我有一个收件人，并且我知道这是有效的，因为我通过 Sparkpost 仪表板发送了测试邮件。但为什么我收到此错误“至少需要一个有效的收件人”？？？!!!我的问题出在哪里

Answer 1

我找到了答案，首先我要感谢 Sparkpost 支持团队，问题出在 Spark 模块中的电子邮件解析器中，并且创建该问题是为了在我的代码中解决它，我进行了此更改来修复它:
收件人=[ dict(address=dict(email=email_address)) ],