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c# - LinqKit Predicate Or with Contains 的计算结果等于

转载 作者:行者123 更新时间:2023-11-30 22:58:22 28 4
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我正在为我的应用程序执行搜索。搜索有效,除非用户的搜索通过搜索相关实体进行级联。我调试了代码并测试了 Entity Framework 生成的 SQL。我发现问题是 Contains() 在 SQL 中应为“LIKE”时转换为“=”。 Contains() 按照我对 FirstName、MiddleName 等的初始谓词的预期工作,但在 if (cascade) 代码块中不起作用。

我的 C# 搜索逻辑:

public IList<Individual> Find(string search, bool cascade, bool includeInactive)
{
_context.Database.Log = s => System.Diagnostics.Debug.WriteLine(s);
IQueryable<Individual> query = _context.Individuals;
if (!string.IsNullOrWhiteSpace(search))
{
search = search.Trim();
string[] searchParts = search.Split(' ');
ExpressionStarter<Individual> predicate = PredicateBuilder.New<Individual>(false);
foreach (string searchPart in searchParts)
{
predicate = predicate.Or(c =>
c.FirstName.Contains(searchPart) || c.MiddleNames.Contains(searchPart) ||
c.LastName.Contains(searchPart) || c.PreferredName.Contains(searchPart));
if (cascade)
{
predicate = predicate.Or(c =>
c.IndividualOrganisationGroups.Select(og => og.OrganisationGroup).Select(g => g.Group.Name)
.Contains(searchPart));
}
}
query = query.Where(predicate);
}
if (!includeInactive)
{
query = query.Where(c => c.Active);
}
return query.ToList();
}

从 EF 生成的 SQL:

SELECT 
[Extent1].[ID] AS [ID],
[Extent1].[RegistrationTypeID] AS [RegistrationTypeID],
[Extent1].[Title] AS [Title],
[Extent1].[FirstName] AS [FirstName],
[Extent1].[MiddleNames] AS [MiddleNames],
[Extent1].[LastName] AS [LastName],
[Extent1].[PreferredName] AS [PreferredName],
[Extent1].[RegistrationNumber] AS [RegistrationNumber],
[Extent1].[Username] AS [Username],
[Extent1].[AzureID] AS [AzureID],
[Extent1].[Notes] AS [Notes],
[Extent1].[Active] AS [Active],
[Extent1].[CreatedDate] AS [CreatedDate],
[Extent1].[CreatedBy] AS [CreatedBy],
[Extent1].[UpdatedDate] AS [UpdatedDate],
[Extent1].[UpdatedBy] AS [UpdatedBy]
FROM [dbo].[Individual] AS [Extent1]
WHERE ([Extent1].[FirstName] LIKE @p__linq__0 ESCAPE '~') OR ([Extent1].[MiddleNames] LIKE @p__linq__1 ESCAPE '~') OR ([Extent1].[LastName] LIKE @p__linq__2 ESCAPE '~') OR ([Extent1].[PreferredName] LIKE @p__linq__3 ESCAPE '~') OR ( EXISTS (SELECT
1 AS [C1]
FROM [dbo].[IndividualOrganisationGroup] AS [Extent2]
INNER JOIN [dbo].[OrganisationGroup] AS [Extent3] ON [Extent2].[OrganisationGroupID] = [Extent3].[ID]
INNER JOIN [dbo].[Group] AS [Extent4] ON [Extent3].[GroupID] = [Extent4].[ID]
WHERE ([Extent1].[ID] = [Extent2].[IndividualID]) AND (([Extent4].[Name] = @p__linq__4) OR (1 = 0))
))
-- p__linq__0: '%screen%' (Type = AnsiString, Size = 8000)

-- p__linq__1: '%screen%' (Type = AnsiString, Size = 8000)

-- p__linq__2: '%screen%' (Type = AnsiString, Size = 8000)

-- p__linq__3: '%screen%' (Type = AnsiString, Size = 8000)

-- p__linq__4: 'screen' (Type = AnsiString, Size = 8000)

有问题的 SQL(最后一个 WHERE 子句):

WHERE ([Extent1].[ID] = [Extent2].[IndividualID]) AND (([Extent4].[Name] = @p__linq__4) OR (1 = 0))

它应该是什么样子:

WHERE ([Extent1].[ID] = [Extent2].[IndividualID]) AND (([Extent4].[Name] LIKE @p__linq__4) OR (1 = 0))

所以我的问题是,如何在我的 Entity Framework SQL 中将此代码转换为 LIKE?

predicate = predicate.Or(c =>
c.IndividualOrganisationGroups.Select(og => og.OrganisationGroup).Select(g => g.Group.Name)
.Contains(searchPart));

最佳答案

它与 LINQKit PredicateBuilder 无关。原因是结果

c.IndividualOrganisationGroups.Select(og => og.OrganisationGroup).Select(g => g.Group.Name)

IEnumerable<string> (或 IQueryable<string> ),所以你正在点击 Enumerable (或 Queryable )Contains方法而不是 string.Contains和其他地方一样。

而不是 Select + Contains ,你真正需要的是 Any扩展方法。

您的示例中最简洁的语法是:

c => c.IndividualOrganisationGroups
.Any(og => og.OrganisationGroup.Group.Name.Contains(searchPart))

当然,如果您需要检查 Group 的更多属性(甚至没有那个),然后使用 Select + Any :

c => c.IndividualOrganisationGroups
.Select(og => og.OrganisationGroup.Group)
.Any(g => g.Name.Contains(searchPart))

或者通过以“正常”方式编写查询,将带有过滤器的集合转换为单个 bool 的最自然方式。例如Select , Where等等,并把无参数 Any最后:

c => c.IndividualOrganisationGroups
.Select(og => og.OrganisationGroup.Group)
.Where(g => g.Name.Contains(searchPart))
.Any())

关于c# - LinqKit Predicate Or with Contains 的计算结果等于,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53053687/

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