php - 搜索引擎/分页

Question

我正在尝试制作一个搜索引擎，但我遇到了这个错误

Notice: Undefined variable: construct in C:\xampp\htdocs\test\search.php on line 24. 

我正在尝试显示结果并显示分页。

这是我的代码:

<?php

$button = $_GET ['submit'];
$search = $_GET ['search']; 
$x = 0;

if(!$button)
echo "you didn't submit a keyword";
else
{
if(strlen($search)<=1)
echo "Search term too short";
else{
echo "You searched for <b>$search</b> <hr size='1'></br>";
mysql_connect("localhost","root","test");
mysql_select_db("test");

$search_exploded = explode (" ", $search);

foreach($search_exploded as $search_each)
{
$x++;
if($x==1)

我不知道为什么它是未定义的。

这是我的第 24 行:$construct .= "username LIKE '%$search_each%'";

else
$construct .= " AND details_in LIKE '%$search_each%'";

}

$construct ="SELECT * FROM intime WHERE $construct";
$run = mysql_query($construct);

谢谢。

Answer 1

您收到该警告是因为您正在使用用于追加的 .=。

$construct .= " username LIKE '%$search_each%'";

您之前没有定义 $construct 但您正试图向其附加一个字符串，因此出现了警告。您应该在使用之前定义 $construct。例如:

<?php

$button = $_GET ['submit'];
$search = $_GET ['search']; 
$x = 0;
$construct = ''; // Defined construct here

//
// .. rest of your code
//