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编辑:是否可以查询这个?我有 2 张 table 。
tithing table
tithings.MarrID = FK to Marriage table
tithings.Tithing_ID PK
tithingspayment table
tithingspayment.TP_ID = PK
tithingspayment.Tithing_ID = FK to tithings table "Tithing_ID"
Paid_Amount
Paid_Month_Year = Date
Marr_ID | Tithing_ID | TP_ID | Tithing_ID | Paid_Amount | Paid_Month_Year | TP_ID | Tithing_ID | Paid_Amount | Paid_Month_Year |
1 | 2 | 5 | 2 | 10.00 | Jan-2014 | 3 | 2 | 10.00 | Feb-2014 |
抱歉代码太长;我想问的是我不想在我的表格中显示相同的名字:
<?php
$con=mysqli_connect("localhost","root","","RMS");
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
if (isset($_GET["page"])) { $page = $_GET["page"]; } else { $page=1; };
$start_from = ($page-1) * 30;
$sql = "SELECT *
FROM tithings
INNER JOIN marriage ON tithings.Marr_ID = marriage.MarrID
INNER JOIN tithings_payment ON tithings_payment.Tithing_ID = tithings.Tithing_ID WHERE YEAR( STR_TO_DATE( Dateregistered, '%Y' ) ) <= $year LIMIT $start_from, 30";
$result = mysqli_query($con,$sql);
echo "<div class='datagrid'><table>
<thead><tr>
<th>Family Name</th>
<th>Jan</th>
<th>Feb</th>
<th>Mar</th>
<th>Apr</th>
<th>May</th>
<th>June</th>
<th>July</th>
<th>Aug</th>
<th>Sep</th>
<th>Oct</th>
<th>Nov</th>
<th>Dec</th>
<th>Operations</th>
</tr></thead>";
while($row = mysqli_fetch_array($result))
{
$id = $row['Tithing_ID'];
echo "<tbody><tr>";
$MonthRegistered = date("F", strtotime($row['Dateregistered']));
$YearRegistered = date("Y", strtotime($row['Dateregistered']));
$PaidMonthYear = $row['Paid_Month_Year'];
$PaidAmount = $row['Paid_Amount'];
$January = date("Y-m", strtotime($row['Paid_Month_Year']));
if($January == "$year-01")
{$January = $row['Paid_Amount'];}
else{$January = 0;}
$February = date("Y-m", strtotime($row['Paid_Month_Year']));
if($February == "$year-02")
{$February = $row['Paid_Amount'];}
else{$February = 0;}
$March = date("Y-m", strtotime($row['Paid_Month_Year']));
if($March == "$year-03")
{$March = $row['Paid_Amount'];}
else{$March = 0;}
$April = date("Y-m", strtotime($row['Paid_Month_Year']));
if($April == "$year-04")
{$April = $row['Paid_Amount'];}
else{$April = 0;}
$May = date("Y-m", strtotime($row['Paid_Month_Year']));
if($May == "$year-05")
{$May = $row['Paid_Amount'];}
else{$May = 0;}
$June = date("Y-m", strtotime($row['Paid_Month_Year']));
if($June == "$year-06")
{$June = $row['Paid_Amount'];}
else{$June = 0;}
$July = date("Y-m", strtotime($row['Paid_Month_Year']));
if($July == "$year-07")
{$July = $row['Paid_Amount'];}
else{$July = 0;}
$August = date("Y-m", strtotime($row['Paid_Month_Year']));
if($August == "$year-08")
{$August = $row['Paid_Amount'];}
else{$August = 0;}
$September = date("Y-m", strtotime($row['Paid_Month_Year']));
if($September == "$year-09")
{$September = $row['Paid_Amount'];}
else{$September = 0;}
$October = date("Y-m", strtotime($row['Paid_Month_Year']));
if($October == "$year-10")
{$October = $row['Paid_Amount'];}
else{$October = 0;}
$November = date("Y-m", strtotime($row['Paid_Month_Year']));
if($November == "$year-11")
{$November = $row['Paid_Amount'];}
else{$November = 0;}
$December = date("Y-m", strtotime($row['Paid_Month_Year']));
if($December == "$year-12")
{$December = $row['Paid_Amount'];}
else{$December = 0;}
if ($YearRegistered <= $year)
{$FamilyHead = $row['FName_Groom']. ", " . $row['LName_Groom'];
$operation = "<td class=operations>" . "<a class='detail' href='../record_detail.php?id=$id'>Details</a> |  <a class='pay' href='payment.php?id=$id'>Pay</a> |  <a class='edit' href='../record_edit.php?id=$id'>Edit</a></td>";
}else{
$FamilyHead = "<style>
tbody{
display:none;
}
</style>";
$operation = "";
}
echo "<td>" . $FamilyHead ."</td>";
echo "<td>" . $January . "</td>";
echo "<td>" . $February . "</td>";
echo "<td>" . $March ."</td>";
echo "<td>" . $April . "</td>";
echo "<td>" . $May . "</td>";
echo "<td>" . $June . "</td>";
echo "<td>" . $July ."</td>";
echo "<td>" . $August . "</td>";
echo "<td>" . $September . "</td>";
echo "<td>" . $October ."</td>";
echo "<td>" . $November . "</td>";
echo "<td>" . $December . "</td>";
echo $operation;
}
十一奉献(表)
Marr_ID(FK) | Tithing_ID (PK) | Dateregistered | Pledge | Barangay | Address |
5 | 1 | Sept, 13 2014 | 15.00 | Barangay1 | Address |
6 | 2 | Jan, 13 2014 | 15.00 | Barangay1 | Address |
婚姻(表格)
MarrID (PK) | FName_Groom | LName_Groom | MName_Groom |
5 | Name(5) | LName(5) | MName(5) |
6 | Name(6) | LName(6) | MName(6) |
什一奉献(表)
Tithing_P_ID(PK) | Tithing_ID(FK) | Payment_Date_Received | Paid_Amount | Paid_Month_Year |
1 | 1 | Sept, 13 2014 | 15.00 | Sept,01 2014 |
2 | 1 | Sept, 13 2014 | 15.00 | Oct,01 2014 |
3 | 2 | Sept, 13 2014 | 15.00 | Jan,01 2014 |
4 | 2 | Sept, 13 2014 | 15.00 | Feb,01 2014 |
我的查询语句是
$sql = "SELECT *
FROM tithings
INNER JOIN marriage ON tithings.Marr_ID = marriage.MarrID
INNER JOIN tithings_payment ON tithings_payment.Tithing_ID = tithings.Tithing_ID WHERE YEAR( STR_TO_DATE( Dateregistered, '%Y' ) ) <= $year LIMIT $start_from, 30";
Paid_Month_Year = Month(Jan-Dec) 我使用 PHP if else 语句
结果是这样的。
Family Name | Jan | Feb | Mar | Apr | May | June | July | Aug | Sep | Oct | Nov | Dec |
Name(5) | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 15.00 | 0 | 0 | 0 |
Name(5) | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 15.00 | 0 | 0 |
Name(6) | 15.00 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
Name(6) | 0 | 15.00 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
注意:我试过 Distinct In 查询无效。
我希望我的输出看起来像这样;
Family Name | Jan | Feb | Mar | Apr | May | June | July | Aug | Sep | Oct | Nov | Dec |
Name(5) | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 15.00 | 15.00 | 0 | 0 |
Name(6) | 15.00 | 15.00 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
最佳答案
这样的事情应该可行,您必须对组语句中未使用的列做一些事情。在您的情况下,采用 SUM 是有意义的,因为有人可以在同一个月支付两次,也可以在另一个月支付。
SELECT
Family_Name,
SUM(Jan),
SUM(Feb)
....
SUM(Dec)
FROM
tithings
INNER JOIN marriage ON tithings.Marr_ID = marriage.MarrID
INNER JOIN tithings_payment ON tithings_payment.Tithing_ID = tithings.Tithing_ID
WHER
YEAR( STR_TO_DATE( Dateregistered, '%Y' ) ) <= $year
GROUP BY
Family_Name
LIMIT $start_from, 30
关于php - 防止显示名称重复或重新输入名称,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25831007/
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